...............................................Figure 1
Measurements:
Angle β = 26.3026897º = angle of the Pyramid’s Ascending Passage (NCP = to North Celestial Pole).
Sinus 26.3026897º = 0.443113275
AB = 0.23192867km = one side of the Great Pyramid's base
ABCDA = 0.92771468km = four sides of the Pyramid's base = d (diameter of the Circle E)
Circumference of the Circle E = 2.914499162km
If a certain object was to travel with a speed of 2.914499162km/sec., for 24 hours it would travel a distance of 251,812.7276km.
Length of the Earth's equator = 40,077.27418km
251,812.7276 : 40,077.27418 = 6.28318 = 2Pi
40,077.27418 : 251,812.7276 = 0.159155077
0.159155077 x 8 = 1.27324062 = tangent of the Great Pyramid’s angle of rise
251,812.7276 : 1.27324062 = 197,773.0868
197,773.0868 : 40,077.27418 = 4.934793865
4.934793865 x 2 = 9.86958773
√9.86958773 = 3.14159 = Pi
.............................................Figure 2
4.934793865 : 2 = 2.467396931 = Pi/1.273240631
√2.467396931 = 1.570795 = Pi/2
1.570795 : 2 = 0.7853975 = Pi/4
√0.7853975 = 0.886226551 = C (Figure 2)
Diameter of the Circle A = 1 = d
ABCDA = 0.92771468km = d = diameter of the Circle E (Figure 1)
Area of the Circle E = 0.675955914km2 = Area of the Square F
One side of the Square F = 0.822165381km = PL
Sinus 26.3026897º = 0.443113275
0.822165381 : 2 = 0.927714681km = d = ABCDA = four sides of the Pyramid's base
0.822165381 : 2 = 0.41108269 = PL/2
0.41108269 : 0.443113275 = d = 0.927714681km = KR = 1/2 of arc minute of the equatorial longitude.
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