The Great Pyramid - Pyramidology

The Great Pyramid - Pyramidology: THE END

2011-08-09T07:08:00.000-06:00

The Great Pyramid - Pyramidology: THE END: ". 91 units (“rooms”) The three pyramids of Giza are located on Earth just as the three stars in the belt of Orion. From the western side of ..."

The Great Pyramid - Pyramidology: THE SIGN OF THE SOLOMON'S TEMPLE

2011-08-09T07:07:00.000-06:00

The Great Pyramid - Pyramidology: THE SIGN OF THE SOLOMON'S TEMPLE: ". ......................... Thomas Ustick Walter: Solomon's temple * Solomon’s temple (measurements in sacred cubits 'cubit of the old st..."

The Great Pyramid - Pyramidology: ORIGINAL ARCHITECTURAL DIMENSIONS OF THE GRAEAT PY...

2011-08-09T07:05:00.000-06:00

The Great Pyramid - Pyramidology: ORIGINAL ARCHITECTURAL DIMENSIONS OF THE GRAEAT PY...: ". Socket: casing-stone in average corner-socket (The Pyramids and Temples of Gizeh by W. M. Flinders Petrie, Pl. XI) Architectural dimensi..."

ORIGINAL ARCHITECTURAL DIMENSIONS OF THE GRAEAT PYRAMID

2011-08-09T06:58:00.001-06:00

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Socket: casing-stone in average corner-socket (The Pyramids and Temples of Gizeh by W. M. Flinders Petrie, Pl. XI)
Architectural dimension of the Gr. Pyramid's socket sides: 9131.5 inches

F. Petrie: Socket Sides:
N......................9129.8 inches
E......................9130.8 inches
S......................9123.9
w......................9119.2
(The Pyramids and Temples of Gizeh by W. M. Flinders Petrie, page 38)

9131.05
- 9130.8
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0.25 inches = 0.635 cm = 6.35 mm
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http://www.touregypt.net/petrie/c6.html

Who built the pyramid

2011-02-17T10:48:00.002-06:00

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The Great Pyramid at Giza Egypt is the largest stone building ever constructed on Earth.
The Great Pyramid is located at the center of the land mass of Earth.
The architect(s) had advanced science and geography data and knew the size and shape of the continents on a global scale. The basic dimensions of the Pyramid also include measurements of the size and shape of the Earth.
In the period 3000 - 2500 BC man did not have the tools or knowledge necessary to build the pyramids.
Who built the pyramids? Aliens or men?
The best answer is: aliens (angels) and men.

Quartz occurs abundantly in many rocks, including granite.

On a hardness scale (Moh's relative scale) of 1 to 10 (talc at 1, a penny at 3, a knife at 5.5, glass at 6, and a diamond at 10) most granite is rated between 6 and 7.

http://www.cjfundesigns.com/lc_gem_properties_hardness.htm

Because of the hardness of minerals that make up granite, it requires diamonds along with water to cut and polish granite.

http://mammothgranite.com/

Has it ever been demonstrated that copper or bronze can cut granite?
Never!
Why?
Because that is impossible!

Granite in the King's Chamber

The Kings Chamber (and the Coffer) is constructed of large blocks of granite.

More granite-casing stones on the East face of Menkaure's Pyramid showing an area of finished stones:

http://www.egyptarchive.co.uk/html/menkaure_07.html

http://www.egyptarchive.co.uk/html/menkaure_06.html

SACRED CUBIT (AMAH)

2010-08-20T10:01:00.003-06:00

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Sacred Cubit = 25 inches = 63.5cm

"It may be of interest, albeit of no halakhic import, to note that, based upon Josephus’ description of the circumference of the pillars of the Temple, the renowned physicist Sir Isaac Newton postulated the length of the “sacred” cubit to be between 24.90 and 25.02 inches as distinct from the “profane” cubit of 20.63 inches that he believed was the measurement employed by the Egyptians in construction of the Great Pyramid. Newton’s calculations are the subject of his “De magnitudine cubiti sacri.” An English translation of that essay titled “A Dissertation Upon the Sacred Cubit of the Jews and the Cubit of Several Nations: in which, from the Dimensions of the Greatest Pyramid, as taken by Mr. John Greaves, the ancient Cubit of Memphis is determined” was published in the Miscellaneous Works of John Greaves, Professor of Astronomy in the University of Oxford, ed. Thomas Birch, II (London, 1737), 405-433."

"18. For a comprehensive survey of the bases and ramifications of those opinions see R. Jacob Gershon Weiss, Midot u-Mishkalot shel Torah (Jerusalem, 5745), pp. 198-264.
19. R. Abraham Chaim Noe, Shi’urei Torah (Jerusalem, 5707), p. 249, calculates the amah, or cubit, as 48 centimeters (18.897 inches). The identical calculation was earlier advanced by R. Shalom Mordecai Schwadron, Da’at Torah 35:116, and Darkei Teshuvah 19:27. Accordingly, the mil, which equals 2,000 cubits, is equal to a distance of 960 meters (3,149.60 feet). Rabbi Noe gives alternative calculations of the amah as equal to 47 centimeters (18.5 inches) or 49 centimeters (19.29 inches). The mil would then be the equivalent of 940 (3,083.98 feet) or 980 meters (3,215.22 feet).
20. Hazon Ish, Kuntres ha-Shi’urin, Orah Hayyim: Mo’ed 39:5-6, and 39:9, calculates the amah as 58 centimeters (22.83 inches) and, accordingly, a mil would equal 1,160 meters (3,805.77 feet). Hazon Ish also cites a report to the effect that R. Shmu’el Salant accepted calculations that would render the amah 60 centimeters or 23.62 inches and the mil 1200 meters or 3937.01 feet. Nevertheless, for purposes of stringency, R. Shmu’el Salant is reported to have accepted calculation that would yield 48 centimeters or 18.90 inches for the amah and 960 meters or 3149.61 feet for the mil.
Cf., R. Ya’akov Kanievsky, Shi’urin shel Torah (Bnei Brak, 5729), who, in a note on p. 63, calculates the amah as 57 2/3 centimeters (22.70 inches) and possibly, according to Rashba, as 59.66 centimeters (23.49 inches). The mil would then be the equivalent of either a bit more than 1,153.2 meters (3,783.46 feet) or a bit more than 1,193.2 meters (3,914.6 feet). Actually, according to Rabbi Kanievsky’s own premises, the calculation of the amah as 57 2/3 centimeters is somewhat imprecise. Rabbi Kanievsky reports that “according to that which has been received by us from gedolei hora’ah, that the amah equals 13 vershak . . .” The vershak is a Russian measuring length equal to 1.75 inches or 4.445 centimeters. If so an amah is the equivalent of 57.78 centimeters (22.73 inches) and thus a mil is equal to 1,155.7 meters (3,791.66 feet). See Encylopedia Britannica, 15th ed. (Chicago, 1995), XIX, 735 (where the term is transliterated as verchok).
A table compiled by Moshe, Rosa and Shimon Bodenheimmer, Shi’urin u-Middot Hazal (Jerusalem, 5725), gives the measurement of the amah as 57.6 centimeters (22.67 inches). Cf., the table published by Y. Avi-Zevi, Shanah be-Shanah, 5730, p. 125, that gives the measurement of the amah as 56 centimeters and that of the mil as 1120.37 meters. Those measurements presumably reflect the view of R. Chaim Jacob Sheftel, Erekh Milin (Berditchev, 5667), erekh ezba, according to whom the amah measures approximately 56 centimeters. See Encyclopedia Talmudit, II (Jerusalem, 5760), 29, note 56.
Other less frequently cited opinions with regard to the length of an amah include those of Meshiv Davar, I, no. 24; Arukh ha-Shulhan, Yoreh De’ah 201:3; Teshuvot Hatam Sofer, Orah Hayyim, no. 181; and the earlier noted view of Erekh Milin, erekh ezba.
Meshiv Davar rejects what he terms “the customarily accepted calculations” according to which the length of the amah would equal 60 centimeters and advances considerations that would yield the measurement of an amah as 48 centimeters. Nevertheless, in his concluding remarks he retracts that view and advances a calculation that would result in an amah measured “in excess of” 48 centimeters and endorses the practice of Frankfurt am Main according to which the length of the amah is calculated as 57 centimeters or 22.44 inches.
Arukh ha-Shulhan states that the length of an amah is 12 “veierskes,” which is apparently the Yiddish term for the Russian vershak. Thus, according to Arukh ha-Shulhan, the length of an amah equals 53.34 centimeters or 21.0 inches. Cf., Encylopedia Talmudit, II, 29, where the length of an amah is given as 54 centimeters according to Arukh ha-Shulhan.
Teshuvot Hatam Sofer states that the length of a fingerwidth is a “zoll.” Since a biblical amah is equal to 24 fingerwidths, the length of an amah according to Hatam Sofer equals 24 zoll. Da’at Torah, Yoreh De’ah, Kuntres Aharon 35:116 states that the zoll is equal to 2.6 centimeters. That calculation is apparently also assumed by Darkei Teshuvah and Encyclopedia Talmudit. [Cf., however, Encyclopedia Britannica, loc. cit., which describes the zoll as a Swiss unit of measure equal to 3 centimeters.] Encyclopedia Talmudit, ad locum, indicates that, according to Hatam Sofer, the length of an amah is 62.4 centimeters or 24.567 inches. Thus a mil, according to Hatam Sofer, would equal 1248.0 meters or 4094.49 feet. Darkei Teshuvah 19:27 notes that the amah was marginally enlarged by rabbinic decree and, accordingly, should be calculated as 241/2 zoll. Darkei Teshuvah endorses the position of Hatam Sofer and states that the length of an amah according to Hatam Sofer is 63.8 centimeters. Thus, according to Darkei Teshuvah, an amah equals 25.12 inches and, accordingly, a mil equals 1276 meters or 4186.35 feet. Hatam Sofer’s calculations are thus significantly greater than those of the earlier-cited authorities.
Darkei Teshuvot also cites a certain “Rabbi of Yasi” who calculated the amah as “no more than” 52 or 53 centimeters and an anonymous scholar who differed and calculated the amah as approximately 581/2 centimeters. Darkei Teshuvah also quotes She’erit Yisra’el, Parashat Mezora, who calculates the amah as 211/6 zoll or 56 centimeters and further opines that one who calculates the amah as 221/8 zoll or 57 centimeters is to be commended. Darkei Teshuvah cites an additional source for the latter calculation as well.
Da’at Torah, Yoreh De’ah, Kuntres Aharon 35:116, cites authorities who variously posit the length of an amah as 47 centimeters, 55.25 centimeters, a bit more than 57 centimeters and 58.5 centimeters, as well as one authority who asserts that according to Rashi the amah equals 43.8 centimeters, according to Shakh 45.02 centimeters, according to Taz 47.34 centimeters and according to Rambam 50 centimeters. See also the measurements ascribed to earlier authorities by Rabbi Weiss, Midot u- Mishkalot shel Torah, pp. 198-264 as well as the table presented ibid., introduction, p. 8. See also R. Moshe Shimshon Bacharach, Hut ha- Shani, no. 97.
For a table correlating many of these measurements of the amah with the volume of the liquid revi’it see Midot u-Mishkalot shel Torah, introd., p. 8. Rabbi Kanievsky, Shi’urin shel Torah, p. 51, cites a discussion in the Palestinian Talmud, Terumot 10:7, that is understood by some authorities, including Riva, Commentary on the Pentateuch, Parashat Mishpatim; Ma’adanei Yom Tov, Berakhot 3:30; and Tosafot Yom Tov, Pe’ah 6:6, as indicating that a revi’it equals 240 grams. If so, an amah would appear to equal 73.368 centimeters or 28.885 inches. Rabbi Kanievsky categorizes that calculation of the revi’it as “extremely large” and as “not imagined by earlyday authorities.”

http://www.traditiononline.org/

Amah = Sacred Cubit

Amah = Hamah = one of the three words for the Sun

The distance from the Earth to the Sun = 149.597.870 km = 1 Astrononical Unit ( 1 AU) = S-E

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Radius of the Sun (R) = 695,691.4306 km
Tangent β = 0.00465041

Length A-C = 1 sacred cubit = 63.5cm

Earth's equator (length) = 40,077.27418 km

Equator = circle= 360 degrees = 21,600 minutes

40,077.27418 : 21,600 = 1.85542936 km

1 degree (Equator) = 1.85542936 km

1 : 100.000 = 1 cm on the particular drawing = 100.000 cm in the realty

A-C = 1 sacred cubit = 25 inches = 63.5 cm

Circle Z (circumference) = 1.85542936 cm

Diameter of the circle Z = 0.590602007 cm

Radius (R) of the circle Z = 0.295301004 cm

0.295301004 : 2 = 0.147650502 cm = 1/100,000 of the G. Pyramid's height

0.295301004 : 63.5 = 0.00465041 = tangent β

Sacred Cubit was created from the Earth's and the Sun's measurements.

The Great Pyramid and the Earth: Divine Proportion of the Great Pyramid

2010-08-20T08:57:00.000-06:00

The Great Pyramid and the Earth: Divine Proportion of the Great Pyramid: "36th course of the Great Pyramid: the height of the 36th course from the natural rock base, or 35th from the pavement (H) = 1162.602377 in..."

Divine Proportion of the Great Pyramid

2010-07-21T13:08:00.005-06:00

36th course of the Great Pyramid: the height of the 36th course from the natural rock base, or 35th from the pavement (H) = 1162.602377 inches high from the base of the ground's solid rock.

A-B = length of the Grand Gallery: 1881.130161 inches
Grand Gallery: length of floor-line from south (A) to north wall (B) = 1881.148496 inches.

Divine proportion, the number Phi = 1.618033988

1162.602377 x 1.618033988 = 1881.130161 inches

1881.148496 - 1881.130161 = 0.018335 inches = 0.465709 millimeters
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THE GREAT PYRAMID - EARTH = 1 : 43 200

2010-07-01T09:56:00.002-06:00

Figure 1

1.
A-B = 365.242 Sacred Cubits = 9131.05 inches = 231.92867 m = 0.23192867 km

4A-B = square D = 0.92771468 km:

0.92771468 x 43 200 = 40 077.27418 km = Earth's equator

2.
H = 232.5204754 Sacred Cubits = 5813.011885 inches = 147.6505019 m:

147.6505019 m x 43 200 = 6378.501681 km = Earth's equatorial radius

3.
H = radius of the circle E = 147.6505019 m
Area E = 68 488.7691 m2 = Area C √68 488.7691 = 261.7035902 m = one side of the square C

261.7035902 m x 43 200 = 11 305.59509 km

Figure 2

Side c of the square B (Figure 2)= 11 305.59509 km

Area of the square B = 12,7816,480.3 km2 = Area of the crcle A

Diameter of the circle A =12 757.00336 km = equatorial diameter of the Earth

4.
One side of the square C (Figure 1) = 261.7035902 m = radius of te circle F

Area of the circle F = 53 790.90805 m2 = Area of the square D

√53 790.90805 = 231.9286702 m = A-B

5. 11 305.59509 : 43 200 = 261.35901 m = 412.131638 Sacred Cubits = 10 303.29095 inches = 25 lengths of the King's Chamber = 50 widths of the King's Chamber.

43 200 seconds = 12 hours

The Pyramid of peace, Astana, Kazakhstan

2009-11-17T11:27:00.004-06:00

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.............................Pyramid of Peace, Astana, the capital of Kazakhstan

The English have a measurement of length, which they call skein : 120 yards = 109,728 meters.
If a man was walk one day, with his every step 1 sacred cubit (63,5 cm or 25 inches) and with the speed of two steps in a second (127 cm), in 24 hours he would travel 109,728 km (1.000 skeins). For one year of 365,242 days, he would travel around the planet Earth. That is, he would travel the length of the Equator: 40.077,27418 km:

1 skein = 120 yards = 109.728 meters

C = 109.728/2 = 54.864m

Area of the Square B = 310.058496 m2 = Area of the Circle A

d = 61.90742077 m

The Pyramid of Peace (officially) is 62 m high.

62 - 61.90742077 = 0.092579231 m = 9.2579231cm = 3.644851614 inches

[url]http://en.wikipedia.org/wiki/Palace_of_Peace_and_Reconciliation[/url]

Geometry of the Universe

2009-07-10T07:50:00.004-06:00

Geometrical scheme of the Universe

DC = diameter of the circle Z = d
GD = radius of the circle Z = r
Angle β1 = Pyramid's ascent = 51,85399754°
Tangent β1 = 1,273240621
Circumference: C = (d/tang.β1) x 4
Area: A = (r²/tang.β1) x 4

Angle β = ascent of the King's Chamber north channel = 32,48165854°
Tangent β = 0,63662031
Circumference: C = (d/tang.β) x 2
Area: A = (r²/tang.β) x 2

Angle β2 = 17,65680115°
Tangent β2 = 0,318310155 = 1 : 3,14159
Circumference: C = d/tang.β2 = AB
Area: A = r²/tang.β2

DH = r/tang.β = KG = GL = AE = EC = CF = FB = 1/4 AB
DC = D/tang.β = AC = CB = 1/2 AB

Tangent of the angle α (Alpha) = 3,14159 = Pi
Tangent of the angle Alpha1 = 1,570795 = Pi/2

The rectangle's Area = Area of the sphere around the circle Z

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Time and geometry of the number Pi

2009-05-18T13:19:00.006-06:00

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Length of the King’s Chamber = 412.1316378 inches
Width of the King’s Chamber = 412.1316378/2 = 206.0658189 in-ches = 10 Royals Cubits

412.1216378/4 = 206.0658189/2 = 103.0329095 inches = 5 Royal Cubits

Geometry of the number Pi:

Circumference of the Circle A = 3.14159 days
d = 1 day
Area of the Circle A = 0.7853975 = Area of the Square B
One side (C) of the Square B = 0.886226551
4C = 3.544906205 days

3.544906205 x 103.0329095 = 365.242 days = 1 tropical (solar) year

100 x 3.544906205 = 354.4906205 days = 1 lunar year

354.4906205 : 12 = 29.54088504 days = 1 lunar (sinodyc) month

The time it takes for the Moon to go from one New Moon to the next is called a Synodic Month, and is 29.530589 days on (scientific) average. Because the orbits of the Earth and Moon aren’t circular, and hence the two bodies don’t move at a constant speed, the actual time between lunations may range from about 29.27 to about 29.83 days.

103.0329095 inches = 261.7035901cm

354.4906205 x 261.7035901 = 92,771.46805cm = 927.7146805m = length of the four sides of the Great Pyramid’s base.
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The Great Pyramid and the Earth's axis

2009-04-25T08:07:00.014-06:00

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God created everything by number, weight and measure. (Isaac Newton)

The Great Pyramid sits on the 30th parallel (30º N).

...........................................Figure 1

Earth = circle = 360º
1º of the Earth’s curved surface = 111km
360º = 39,960km = Earth’s perfect circle = Circle A (Figure 1)

.............................................Figure 2

1º of the Earth’s curved surface = 111km
30º = 3330km = AB (Figure 2)

β = 51.85399754º
Tangent β = 1.273240621

AB = 3330km

39,960 : 3330 = 12

AB/2 = 1665km

1665 x 1.273240621 = 2119.945634 = H

2119.945634 x 6 = 12.719.6738km = d (Figure 1)
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Moriah and the Mount of Olives (altitudes - geometry)

2009-04-03T18:06:00.007-06:00

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...............Mount Moriah and the Mount of Olives

1º of the Earth's curved surface = 111km
Circle = 360º
360º x 111 = 39,960km

In order to travel the distance of 39,960 km in one day (24 hours), a certain object would have to travel at a speed of 462.5 m/sec. = radius of the Circle E = = r

Area of the Circle E = 672,005.7359km2 = Area of the Square F

AB = 819.7595598 meters = BC = altitude of the Mount of Olives = H3

819.7595598m = 1290.959937 sacred cubits

Portal of the Solomon's temple (height) = 120 sacred cubits = H2

1290.959937
-120
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1170.959937 sacred cubits

1170.959937 sacred cubits = 743.5595598 meters = 2439.499868 feet = altitude of the Mount Moriah (Temple Mount) = H1
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PYRAMIDOLOGY

2009-02-19T11:14:00.014-06:00

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.....................................GOD AND GEOMETRY

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The Great Pyramid and the metric system

2009-01-27T11:36:00.008-06:00

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............................................Figure 1

Tangent β = 1.273240621

First base (red line) = 365.242 sacred cubits = 9131.05 inches = 23,192.867cm = 231.92867m

√23,192.867 = 152.2920451cm = 2AB

23,192.86 - 152.2920451 = 23,040.57495cm = 230.4057495m = length of the Second base (blue line).

152.2920451 : 2 = 76.1460226cm = AB

76.1460226 x 1.273240621 = 96.9522091 = d

C = 304.5840906cm = 2 x 152.2920451

............................................Figure 2

d = 96.9522091 : 2 = 48.47610449cm

C = 42.9608109cm

4C = 171.8432436cm

171.8432436 : 152.2920451 = 1.128379644

1.128379644² = 1.273240621

171.8432436 x 152.2920451 = 26,170.359cm = 412.1316379 sacred cubits = 10,303.29095 inches = 25 lengths of the King's Chamber.

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Symbolism and fakts

Length of the First base in centimeters = 23,192.867cm
Length of the Second base in centimeters = 23,040.57495cm

Difference between two bases = 152.2920451cm

Length of the First base of the Great Pyramid = 365.242 sacred cubits = 365.242 days = 1 year

365.242 : 152.2920451 = 2.398299923

2.398299923 : 3.14159 = 0.76340322 days

152.2920451 x 0.76340322 = 116.2602377

116.2602377 x 3.14159 = 365.242

152.2920451 : 0.76340322 = 199.4909651

1 sacred cubit = 63.5cm

199.4909651 : 63.5 = 3.14159

1 inch = 2.54cm

199.4909651 : 2.54 = 78.53975004

78.53975004 x 4 = 314.159 = 100Pi

These measurements and numbers can only be found if we use the metric system. The ancient Egyptians did not know of the metric system, which means that they were not the builders of the Great Pyramid.

What do you think, who was the architect who was familiar with the metric system during that ancient time?
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February 11, Al Jizah horizon

2008-12-31T14:21:00.035-06:00

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.................................February 11, position of the Sun

Date: February 11
Location: Al Jizah (Giza)
Sunrise: 06:40
Top R.A. = 21h 35m 51.39s = VE-D (vernal equinox - Sun's position on February 11)
Distance = 0.986982648

The average distance from the Earth to the Sun = 149,597,870 km = 1 Astronomical unit (1AU)

Height of the Great Pyramid = 14,765.05019 cm

February 11: Earth-Sun (distance) = 147,650,501.9 km

147,650,501.9 : 149,597,870 = 0.986982648

Top RA = 21h 35m 51.39s = VE-D = 21.59760833 hours

Right ascension (RA): 1 hour = 15 degrees

21.59760833 hours = 323.964125 degrees

1 year = 365.242 days

365.242 - 323.964125 = 41.277875 days

January = 31 days

41.277875 - 31 = 10.277875 days = 10 days, 6 hours, 40 minutes and 8.4 seconds = February 11, sunrise at Al Jizah (Giza).

The shortest distance between the Earth and the Sun (perihelion) is about 147,166,462 km. This point in the Earth's orbit occurs on January 3.

The Earth is farthest away from the Sun on July 4 (aphelion) when it is about 152,100,000 km from the Sun.

1 year = 365.242 days

365.242 : 2 = 182.621 days = January 3 - July 4

Tangent of the Pyramid's angle of rise = 1.273240621

182.621 : 1.273240621 = 143.4300768 days = February 11 (B) - July 4 (C) = September 21 (A) - February 11 (B)

143.4300768 x 2 = 286.8601536 days = 365.242 : 1.273240621 = September 21 (A) - February 11 (B) - July 4 (C)
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Daylight map (Egypt- Al Jizah, February 11, 06/6 am, Minutes 40):
http://www.timeanddate.com/worldclock/sunearth.html

Sunrise and Sunset Calculator (location Egypt-Cairo):
http://www.timeanddate.com/worldclock/sunrise.html?month=2&year=2009&obj=sun&afl=-12&day=1
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January 7 = December 25

2008-12-24T16:51:00.023-06:00

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..................Position of the Sun on January 7 (click on the picture)

Measurements:

C = position of the Sun on January 7 of the Gregorian calendar = December 25 of the Julian calendar = orthodox Christmas.

VE = Celestial Meridian of the vernal equinox

C-VE = RA (right ascension) = 19.09793455 hours = 19h 5m 52.56436776s = 286.4690182 degrees* = distance from the Sun's position on January 7 to the Celestial meridian of the vernal equinox(VE).

1º of the Earth's equatorial longitude = 111.3257616 km

286.4690182º = 31,891.38163 km = 50,222,648.23 sacred cubits

The entrance axis is located away from the main axis of the Great Pyramid by 286.4690182 inches = 11.45876073 sacred cubits:

50,222,648.23 : 11.45876073 = 4,382,904

Base of the Great Pyramid (one side) = 365.242 sacred cubits:

4,382,904 : 365.242 = 12,000

Two sides of the Pyramid's base = 730.484 sacred cubits:

4,382,904 : 730.484 = 6000

Three sides of the Pyramid's base = 1095.726 sacred cubits:

4,382,904 : 1095.726 = 4000

Perimeter of the Pyramid's base = 1460.968 sacred cubits:

4,382,904 : 1460.968 = 3000

Who has adjusted the measurements of the Great Pyramid to the Sun's ephemeris of the days of Christ's birthday?

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*Geocentric Ephemeris for the Sun:
http://eclipse.gsfc.nasa.gov/TYPE/TYPE.html
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PRAISE THE LORD

2008-12-22T09:59:00.024-06:00

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The Eye of Providence
Twinkling
The voice of Ancient of Days
Speaking
-The Pyramid of Time
Is done
All earth and the Universe
Will be gone
In the coming Last Day
Where the future
Has no way

To all mankind sings
On the wind's wings
In the tears of the sea
Over the dying last bee

Fifty one stars
In the Cancer Constellation
Made by human proclamation
With a crude oil desecrated
Will be disintegrated
In a fired dark space
When the Lord’s face
Appears from the East
To the Judgment Feast

Then Peter Romanus
Caesar of Rome and Constantinople
With the twelve stars on his head
Eater of a godless bread
The false prophet and false god
And high chief priest
Will bi invited on the Feast
In a chain like a beast
That evil expert very-well
Will be send
In the Hell
To the Father of the lie
Oh, glory of all sins
Forever goodbye
Forever goodbye

O man of the world
Praise the Lord
Praise the Lord
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Bethlehem, time, astronomy and esotery

2008-12-18T13:16:00.030-06:00

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.A tropical year (also known as a solar year) is the time it takes the Sun to appear to travel around the sky from a given point of the tropical zodiac back to that same point in the tropical zodiac = 365.242 days.

Sidereal year, time required for the Earth to complete an orbit of the sun relative to the stars = 365.256 days (it is 20 min longer than the tropical year).

King's Chamber:
length = 412.1316378 inches
width = 206.0658189 inches

(412.1316378 : 4) = 206.0658189 : 2 = 103.0329095

Perimeter of the Square B = 103.0329095 km

One side of the Square A (side C) = 25.75822736 km

Area of the Square B = 663.4862769 km2 = Area of the Circle A

Diameter of the Circle A = 29.06505941 km

Circumference of the Circle A = 91.3105 km (91.3105 x 4 = 365.242)

From January 1 of the 1 year of the Creation, when Adam and Eve expelled from Eden to the the birth of Jesus Christ on 25 December 4 BC = 4278.983 years

Tropical year = 365.242 days

4278.983 tropical years = 1,562,864.309 days

Great Pyramid Code: 1 day = 2.466586266 cm

1,562,864.309 days = 38.5493964 km

91.3105 x 38.5493964 = 3519.96466 km

1 degree of the Earth's curved surface = 111 km

3519.96466 km = 31.71139333º = 31º 42' 41" = Equator - Bethlehem*

Sidereal year = 365.256 days

4278.983 sidereal years = 1,562,924.215 days

Great Pyramid Code: 1 day = 2.466586266 cm

1,562,924.215 days = 38.55087403 km

91.3105 x 38.55087403 = 3520.09983 km = 31.71260886º = 31º 42' 45.39" = Equator - Bethlehem.
-------------------------

*Latitude of Bethlehem:
http://www.geody.com/geolook.php?q=BETHLEHEM%2C+West+Bank

Julian days (JD):
http://www.sizes.com/time/dayJulianr.htm
.

The Great Pyramid and the Bible Code

2008-12-16T19:09:00.029-06:00

.
......................Figure 1. King's Chamber and the Grand Gallery

Length of the Grand Gallery = 1881.148496 inches = radius of the Circle (Figure 2)

.............................................Figure 2

Diameter of the Circle = 2 x 1881.148496 = 3762.296992 inches

Circumference of the Circle = 11,819.59461 inches = 30,021.7703 cm

Great Pyramid Code: time can be shown in the measurements of length: 1 day = 2.466586266 cm

30,021.7703 cm = 12,171.38468 days = 33.32416503 years = December 25, 4 BC - April 20, 31 AD

Length of the King's Chamber = 412.1316378 inches

Moon's synodic period = 29,53010038 days*.

412.1316378 x 29.53010038 = 12,170.28863 days = 33.32116414 years = December 25, 4 BC - April 20, 31 AD

December 25, 4 BC = Jesus Christ was born

April 13, 31 AD = crucifixion of Jesus Christ, the Great and Holy Friday, in the evening beginning of Jewish Passover.

April 14, 31 AD = the day when was the Lord Jesus Christ lead out Adam, Eve and other righteousness from the Hell into Heavenly Kingdom = first day of Jewish Festival of Unleavened Bread:

The Bible Code: "The Lord's Passover begins at twilight on the fourteenth day of that month. On the fifteenth day of that month the Lord's Feast of Unleavened bread begins; for seven days you must eat bread made with out yeast." (Lev. 23, 5-6)

April 20, 31 AD = sixth and beginning of the seventh day of the Feast of Unleavened bread.
------------------------------
* The time it takes for the Moon to go from one New Moon to the next is called a Synodic Month , and is 29.53 days on average. Because the orbits of the Earth and Moon aren't circular, and hence the two bodies don't move at a constant speed, the actual time between lunations may range from about 29.27 to about 29.83 days.

a) Astronomy:
Moon: synodic period, lunar month, lunation (average) = 29,53059 days.
b) The Great Pyramid:
Moon: synodic period, lunar month, lunation (average) = 29,53010038
.

Mythology, mysticism, esotery, time and geometry

2008-12-12T15:48:00.085-06:00

..............................Falcon eye and the Eye of Providence?
.

Peregrine falcon eye is a circle with the "snake" uraeus* around (click on the picture)

Peregrine falcon (Horus) and the circle (the uraeus around circle = Time)

Mythology (Greek μυθολογία mythología) meaning "a story-telling, a legendary lore") refers to a body of folklore, myths, legends that a particular culture believes to be true and that often use the supernatural to interpret natural events and to explain the nature of the universe and humanity.

Mysticism: immediate consciousness of the transcendent or ultimate reality or God; a belief in the existence of realities beyond perceptual or intellectual apprehension.

King's Chamber in the Great Pyramid (length) = 412.1316378 inches

412.1316378 days = 1.128379644 years

412.1316378 : 3.14159 = 131.1856855 days

131.1856855 : 4 = 32.79642138 days = 33th day = peregrine falcon's eggs hatch after about 33 days of incubation = side C (Figure 1).

.............................................Figure 1

Esotery (from Greek esōterikos, esōterō): mystery, secret knowledge not accessible to the uninitiated, confined to and understandable by only an enlightened inner circle.

The Great Pyramid's Code: time can be shown in the measurements of length: 1 day = 2.466586266 cm

32.79642138 days = 80.89520256 cm = C (Figure 1)

Area of the Square B = 6544.033797 cm2 = Area of the Circle A

Diameter of the Circle A = 91.28371286 cm

2.466586266 cm = 1 day

91.28371286 cm = 37.0189769 days = diameter of the Circle A (in days)

Pyramid's Ascending passages (angle of rise) = 26.3026897º.
Sinus 26.3026897º = 0.443113275

37.0189769 : 0.443113275 = 83.54292004 days = 206.0658192 cm = width of the King's Chamber (in inches) = 412.1316378/2

206.0658192 x 0.443113275 = 91.3105 cm

1 season = 91.3105 days (91.3105 x 4 = 365.242 days = 1 year)

206.0658192 : 0.443113275 = 465.0409512 days = 1,273240622 years = tangent of the Pyramid's angle of rise (51.85399754º ).

91.28371286 cm = 37.0189769 days

37.0189769 x 0.443113275 = 16.40360009

16.40360009 x 2 = 32.80720018

37.0189769 : 1.128379644 = 32.80720022 days = falcon incubation = C (Figure 2)

..............................................Figure 2

1 day = 2.466586266 cm

32.80720022 days= 80.92178949 cm = C (Figure 2)

Area of the Square B = 6548.336014 cm2 = Area of the Circle A

d = diameter of the Circle A = 91.3105 cm

The fastest bird is the peregrine falcon which can reach speeds about 324 km/h when diving to catch and kill its prey. Its amazing swooping speed makes it the fastest creature on earth.

..............................................Figure 3

C = 323.687158 km (about 324 km)

Area of the Square B = 33,350.42965 km2 = Area of the Circle A

Diameter of the Circle A = 365.242 km

1 year = 365.242 days

Symbolism: 1 km of a falcon's speed = 1 day of a year

King's Chamber = 412.1316378 (inches)

323.687158 : 412.1316378 = 0.7853975 = 3.14159/4

412.131.6378 : 323.687158 = 1.27324062 = tangent of the Pyramid's angle of rise

Angle of the Pyramid's Ascending Passage = 26.3026897º

Sinus 26.3026897º = 0.443113275

323.687158 : 0.443113275 = 730.484 = 365.242 x 2

323.687158 x 0.443113275 = 80.92178939 (see C, Figure 2)

----------------------------
* The Uraeus from the Greek οὐραῖος:
Hora = ancient name of summer;
Horos, Horus = a time, period of time, circle of time, seasons, days, hours Horoscopos: the Greek hora meaning “hour” and scopos meaning “watcher”
Horos = horison (Greek) = a visible circle
Horasis (Greek) = vision, the sense of sight

http://dacia.org/forum.php?homeinclude=topicdetails&forum_id=5&category_id=13&post_id=116

http://www.experiencefestival.com/hora .

Burj Dubai Tower (geometry)

2008-12-11T17:57:00.026-06:00

.

...The Burj Dubai tower, tallest building in the world, is soon to be completed.* (click on the picture)

1º of the Earth's curved surface = 111km

Earth = circle = 360º

360º = 39,960km = Earth's perfect circle = Circle A

In order to travel the distance of 39,960 km in one day (24 hours), a certain object would have to travel at a speed of 462.5 m/sec. = radius of the Circle A

Area of the Circle A = 672,005.7359 m2 = Area of the Square B

C (one side of the Square B) = 819.7595598m = the projected final height of Burj Dubai tower*.

819.7595598 : 462.5 = 1.772453102 = √3.14159

The projected final height of Burj Dubai is officially being kept a secret**.

-------------------------
BURJ DUBAI TOWER:
http://greatpyramid.blogspot.com/2008_05_01_archive.html

*Official height of the Burj Dubai Tower = 818-819m:

http://dubai-tower.blogspot.com/

** http://www.emporis.com/en/wm/bu/?id=182168

http://en.wikipedia.org/wiki/Burj_Dubai

Circling of the Square

2008-12-06T17:02:00.028-06:00

.

...............................................Figure 1

Measurements:

Angle β = 26.3026897º = angle of the Pyramid’s Ascending Passage (NCP = to North Celestial Pole).
Sinus 26.3026897º = 0.443113275

AB = 0.23192867km = one side of the Great Pyramid's base
ABCDA = 0.92771468km = four sides of the Pyramid's base = d (diameter of the Circle E)

Circumference of the Circle E = 2.914499162km

If a certain object was to travel with a speed of 2.914499162km/sec., for 24 hours it would travel a distance of 251,812.7276km.

Length of the Earth's equator = 40,077.27418km

251,812.7276 : 40,077.27418 = 6.28318 = 2Pi

40,077.27418 : 251,812.7276 = 0.159155077

0.159155077 x 8 = 1.27324062 = tangent of the Great Pyramid’s angle of rise

251,812.7276 : 1.27324062 = 197,773.0868

197,773.0868 : 40,077.27418 = 4.934793865

4.934793865 x 2 = 9.86958773

√9.86958773 = 3.14159 = Pi

.............................................Figure 2

4.934793865 : 2 = 2.467396931 = Pi/1.273240631

√2.467396931 = 1.570795 = Pi/2

1.570795 : 2 = 0.7853975 = Pi/4

√0.7853975 = 0.886226551 = C (Figure 2)

Diameter of the Circle A = 1 = d

ABCDA = 0.92771468km = d = diameter of the Circle E (Figure 1)

Area of the Circle E = 0.675955914km2 = Area of the Square F

One side of the Square F = 0.822165381km = PL

Sinus 26.3026897º = 0.443113275

0.822165381 : 2 = 0.927714681km = d = ABCDA = four sides of the Pyramid's base

0.822165381 : 2 = 0.41108269 = PL/2

0.41108269 : 0.443113275 = d = 0.927714681km = KR = 1/2 of arc minute of the equatorial longitude.
---------------------------------------

The Earth and the Great Pyramid

2008-12-03T07:09:00.012-06:00

.
............................The Earth and the Great Pyramid

b = 0.23192867km

h = 0.1476505019km

Equator of the Earth = 40,077.27418km

1º of the equatorial longitude = 111.3257616km = 0.49998686º

111.3257616/2 = 55.6628808km

55.6628808 : 0.23192867 = 240

40,077.27418 : 0.23192867 = 172,800 = 2 x 86,400

Earth’s equatorial diameter = 12,757.00336

12,757.00336 : 0.1476505019 = 86400

Number Pi = 3.14159

Circle = 360º

3.14159 : 30 = 0.008726638 = tangent of 0.49998686º
.

THE HARMONIC NUMBERS OF CREATION

2008-11-27T13:18:00.036-06:00

.

Circle = 360º

Length of the Earth's equator = 40,077.27418 km

Equatorial diameter of the Earth = 12,757.00336 km

Esoteric code number = 4320

Code numbers of the Solomon's Temple (in cubits):
120 (Portal's height)
..60 (length of the Temple)
..30 (height of the Temple)
..20 (width of the Temple)

Height of the Great Pyramid = 147.6505019 = 0.1476505019 km

2 x 0.1476505019 = 0.2953010038 km

Number Pi = 3.14159

1 meter (m) = 10 decimeters (dcm)

Code measurement = 3.14159 dcm (decimeter)

3.14159 x 120 x60 x 30 x 20 = 13,571,668.8 dcm = 1357,166.88 m = 1357.16688 km

1357.16688 : 4320 = 0.314159

In order to travel the distance of 1357.16688 km in one day (24 hours), a certain object would have to travel at a speed of 15.70795 m/sec. = 5Pi.

40,077.27418 : 1357.16688 = 29.53010037 km

12,757.00336 : 29.53010037 = 432.0

1º of the equatorial latitude = 40,077.27418 : 360º = 111.3257616 km

1' of the equatorial latitude = 1.85542936 km

29.53010037 km on the Equator = 0.265258462º = 15' 54.95967683" = Sun's parallax and Semi-diameter of the Sun on the sky (summer, July)*.

360º : 1357.16688 = 0.2652585462º = 29.53010036 km
-----------------------------

* Sun Parallax and Semi-diameter.pdf
http://www.markbreach.co.uk/ephemeral_tables.htm

.

PERFECTION OF THE GEOMETRY

2008-11-25T19:39:00.009-06:00

.

γ = 32.48165854º = angle of the north "air" channel of the King's Chamber.
Tangent 32.48165854º = 0.63662031 = 1.273240621/2

β = 51.85399754º = The Great Pyramid's angle
Tangent 51.85399754º = 1.273240621
Sinus 51.85399754º = 0.786439353

AB = dijameter of the circle K = 1.128379644 = √1.273240621

1.273240621 years = 412.1316378 days = length of the King's Chamber (in inches)

GF = 1/2 GI = 0.5

δ = angle of the Pyramid's passages = 26.3026897º
Sinus 26.3026897º = 0.443113275

0.5 : 1.128379644 = 0.443113275

0.5 x 1.1283279644 = 0.564189822 = radius CB

0.564189822 : 0.443113275 = 1.273240621

√3.14159 = 1.772453102

1.772453102 : 0.443113275 = 4

4 : 3.14159 = 1.27324062

1,772453102 : 1.273240621 = 1.392080234

1.392080234 : 3.14159 = 0.443113275

James Fergusson, in his great work, the History of Architecture, describes the Great Pyramid as "the most perfect and gigantic specimen of masonry that the world has yet sin." (James Fergusson, History of Architecture)
.

SQUARING THE CIRCLE (conclusion)

2008-11-22T15:32:00.011-06:00

.

δ = 26.3026897º = angle of the Great Pyramid’s passages.
Tangent = 0.494289195
Sinus = 0.443113275

β = 51.85399754º = Gr. Pyramid’s angle.
Tangent = 1.273240621
Sinus = 0.786439353

γ = 32.48165854º = angle of the north “air” channel of the King’s Chamber.
Tangent = 0.63662031 = 1.273240621/2

α = 38.14600246º
Tangent = 0.7853975 = Pi/4

ω = 48.4517858º
Tangent = 1.128379644 = ω = √1.273240621

ζ = 41.5482142º
Tangent = 0.886226551 = √0.7853975 = √Pi/4

HP = 0.443113275 = sinus 26.3026897º

CB = 0.564189822 = radius of the Circle K = r

0.443113275 : 0.564189822 = 0.7853975 = Pi/4

CD = 0.5 = a/2 (a = one side of the square)

Constant for the squaring the circle: ω (omega)
ω = 1.128379644

r = a/2 x tan ω = 0.5 x 1.128379644

a/2 = r/tan ω = r/1.128379644
.

THE GREAT PYRAMID - GREENWICH (IV)

2008-11-17T09:37:00.013-06:00

From the Great Pyramid to Prime Meridian of the world

The Great Pyramid - Greenwich Meridian = 31º 8' 6.486504" = 31.13513514º E

1º = 111 km

31.13513514º = 3456 km (distance beetwin the two blue lines).

a) Base of the Pyramid = 365.242 sacred cubits = 231.92867 meters

b) Coptic word for Pyramid is pyrmet = tenth part

231.92867 : 10 = 23.192867

3456 x 23.192867 = 80,154.54835

80,154.54835 : 2 = 40,077.27418 km = length of the Earth's Equator in kilometres.

c) 40,077.27418 : 3456 = 11.5964335 = 23.192867/2

d) The sides of the Great Pyramid rise at an angle of 51.85399754º (tangent = 1.273240621):

.
3456 : 1.273240621 = 2714.33358 km

Pi = 3.14159

If a certain object was to travel with a speed of 3.14159 dekameters/sec., for 24 ours (1 day) it would travel a distance of 2714.33358 km*.

--------------------------

* 1 dekametre (1 dkm) - a metric unit of length equal to ten meters.

WHY GREENWICH (III)

2008-11-08T10:44:00.003-06:00

.
............... Earth's Prime Meridian and the Pyramid's Meridian (blue line).

Greenwich Meridian - Pyramid's Meridian = 31.13513514º = 3456 km

Pi = 3.14159

100Pi = 314.14159

3456 : 314.159 = 11.00079896 km

1 day = 86,400" (seconds)

11.00079896km = 11,000.79896 meters = 110,007.9896 decimeters (dcm)

110,007.9896dcm/86,400" = 1.273249621 = tangent of the Pyramid's angle of rise.

.

THE END

2008-10-24T15:10:00.001-06:00

91 units (“rooms”)

The three pyramids of Giza are located on Earth just as the three stars in the
belt of Orion.
From the western side of the middle pyramid, that corresponds to the middle
star of Orion’s belt, Alnilam (ε Ori), there are 91 units (“rooms”).

These 91 units show that this star will be by 91º away (1 unit = 1º ) from North
celestial pole at the time of the End of the World (2000-2070 AD).

Current position is very close to 91º ( exactly 91º = 2037 AD).
.

WHY GREENWICH (II)

2008-10-21T22:41:00.002-06:00

.
............... Earth's Prime Meridian and the Pyramid's Meridian (blue line).

Earth's equatorial diameter = 12,757.00336 km

Greenwich Meridian - Pyramid's Meridian = 31.13513514º = 3456 km

12,757.00336 : 3456 = 3.691262546 km

3.691262546 x 4 = 14.76505019 km

Height of the Great Pyramid = 0.1476505019 km

.

WHY GREENWICH?

2008-10-17T11:30:00.015-06:00

.
The Greenwich Meridian, based at the Royal Observatory, Greenwich, was established by Sir George Airy in 1851.

........Earth's Prime Meridian and the Pyramid's meridian (blue line).

Measurements:

Earth's Equator = 40,077.27418km*

Base of the Great Pyramid (one side) = 231.92867m**

Greenwich Prime Meridian - Pyramid's Meridian = 31.13513514º E (31º 8' 6.486504" E).

1º = 111 km***:

31.13513514º = 3456km

40,077.27418 : 3456 = 11.5964335km

Base of the Great Pyramid (one side) = 231.92867m = 2 x 115.964335m

-----------------------
*Equator:

http://www.google.ca/search?hl=en&sa=X&oi=spell&resnum=0&ct=result&cd=1&q=Earth%27s+equator+40,077km&spell=1

http://www.google.ca/search?hl=en&sa=X&oi=spell&resnum=0&ct=result&cd=1&q=Earth%27s+equator+40,077km&spell=1

** Real length of the Pyramid's base (PYRAMIDISTS VS PYRAMIDOLOGITS):

http://greatpyramid.blogspot.com/search?q=pyramidologist+vs+pyramidist

**1º = 111km:

http://eesc.columbia.edu/courses/ees/lithosphere/labs/lab1.html
.

SYMBIOSIS OF THE NUMBERS

2008-10-03T10:40:00.011-06:00

.
..............................................Figure 1

Base AB = 365.242 sacred cubits = 9131.05 inches = 231.92867 meters.

Height CD = 232.5204754 sacred cubits = 5813.011885 inches = 147.6505019 meters = Diameter of the Circle S.

Pyramid's angle (ascent) = 51.85399754º
Tangent 51.85399754º = 1.273240621

Circumference of the Circle S = 463.8573402 meters = speed of the Earth's rotation around the own axis (in a secodn).

Area of the Circle S = 17,122.19227 m2 = Area of the Square R

EF = 130.8517951 meters = FG = GH = HE

147.6505019 : 130.8517951 = 1.128379643

1.128379643 x 1.128379643 = 1.273240621 = tangent of the Pyramid's angle.

1 year = 365.242 days

1.128379643 years = 412.1316378 days = length of the King's Chamber (in inches).

412.1316378 : 2 = 206.0658189 days = 4C (Figure 2) = width of the King's Chamber (in inches)

C = 51.51645473 days

............................................. Figure 2

..............................................Figure 3

1 year = 365.242 days

365.242 : 51.51645473 = 7.089812409 days = Circumference of the Circle A (Figure 3).

7.089812409 : 3.14159 = 2.256759287 days = Diameter of the Circle A (Figure 3).

Radius of the circle A = 1.128379644 days

Area of the Circle A = 4 = Area of the Square B

One side of the Square B = 2 ( THE NUMBERS OF THE COFFER http://greatpyramid.blogspot.com/2008/09/numbers-of-coffer.html )

THE NUMBERS OF THE COFFER

2008-09-23T08:08:00.012-06:00

PART ONE

Outside of Coffer (measurements in inches):

length = 89.65157346
breadth = 38.55135205
height = 41.23149865

Volume = 14,2503.8674 cub. inches = 2335.221682 liters

Volume of the inner secton = 142,503.8674/2 = 71,251.93368 cub. inches = 1167.610841 liters

1 year = 365.242 days

1167.610841 : 365.242 = 3.196814279

3.196814279 : 10 = 0.3196814279

1 day = 24 hours = 1440 minutes = 86,400 seconds:

0.3196814279 x 86,400 = 27,620.47537

Equator of the Earth = 40,077.27418 (km):

40,077.27418 : 27,620.47537 = 1.450998712

Breadth of the Coffer = 38.55135204 (inches):

38.5513502 : 1.450998712 = 26.56883833 inches = inside breadth of the Coffer.

PART TWO

The Great Pyramid (height) = 147.6505019 m

1 year = 365.242 days

147.6405019 : 365.242 = 0.404253897

1 day = 86,400 seconds:

0.404253897 x 86,400 = 34,927.53671

Equator of the Earth = 40,077.27418 (km)

40,077.27418 : 34,927.53671 = 1.147440614

Length of the Coffer = 89.65157346 (inches):

89.65157346 : 1.147440614 = 78.13177638 inches = inside length of the Coffer.

PART THREE

1 year = 365.242 days

365.242 : 1.147440614 = 318.3101553

318.3101553 : 250 = 1.273240621 = tangent of the Pyramid’s angle.

C = 318.3101553
d = 359.1746996
A = 1128.379645

√1.273240621 = 1.128379644

King’s Chamber (length) = 412.1316378 (inches)

412.1316378 : 1128.379645 = 0.356242 = 365.242/1000

Circle (circumference) = 2rPi

(2 x 1128.379645) x 3.14159 = 7089.812409

412.1316378 : 7089.812409 = 0.05813011883 (height of the Great Pyramid = 5813.011885 inches).

PART FOUR

Coffer’s inner volume = 1167.610841

1167.610841 : 1.147440614 = 1017.578449

1017.578449 : 1000 = 0.1017578449

0.1017578449 x 86,400 = 8791.877794

8791.877794 x 3.14159 = 27,620.47537 (see Part One)

PART FIVE

Volume of the inner secton of the Coffer = 1167.610841 liters = 71,251.93368 cub. inches.

The Coffer:

inside length = 78.13177638 inches
inside breadth = 26.56883833 inches

(71,251.93368 : 78.13177838) : 26.56883833 = 34.32388121 inches = inside depth of the Coffer.

PART SIX

Outside: length = 89.65157346 inches
Inside: length = 78.13177638 inches

89.65157346 : 78.13177638 = 1.147440614

Outside: breadth = 38.5513502 inches
Inside: breadth = 26.56883833 inches

38.5513502 : 26.56883833 = 1.450998712

Outside:height = 41.23149865 inches
Inside: depth = 34.32388121 inches

41.23149865 : 34.32388121 = 1.201248146

(1.201248146 x 1.147440614) x 1.450998712 = 2

2 : 1.273240621 = 1.570795 = Pi/2
.

QUESTION WITHOUT ANSWER

2008-09-20T12:22:00.025-06:00

"The basalt pavement is a magnificent work, which covered more than a third of an acre. The blocks of basalt are all sawn and fitted together; they are laid upon a bed of limestone*..."

Hot molten basalt lava in the Temple of metrology was placed on the limestone surface. When this lava cooled down it was cut into blocks.

On the above pictures it perfectly shows the connection between the basalt lava and the limstone** (click to enlarge). Are there any egiptologysts, arheologists or architects who will explain all these methods of construction? No, they are quiet and mute because they do not have the answer. When all of them are silent nobody else will even start to think about all this***.

------------------------------

* http://www.touregypt.net/petrie/c6.html#28

**Photo: http://www.ancient-wisdom.co.uk/egyptghizapage.htm

http://www.gizapower.com/pma/index.htm

*** Basalt pavement (connection between the basalt lava and the limstone, photos): http://www.solomonseries.com/freedownloads1.htm

http://www.touregypt.net/petrie/c6.html#28

FREE E-BOOKS

2008-09-15T11:24:00.006-06:00

Free e-books only for you, dear my friends:

http://www.scribd.com/people/view/1379034-petko-nikolic-vidusa

Thank you for visiting my blog!

TEMPLE OF THE METROLOGY (II)

2008-09-01T09:29:00.057-06:00

.
.......................31 AD, April 29: ephemeris of the Sun +14º

Gregorian calendar: 2000 AD, April 27: ephemeris of the Sun = +14º

April 27th of the Gregorian calendar* = April 14th of the Julian calendar

31 AD, April (Julian calendar) :
- April 13 = Great and Holy Friday
- April 14 = Great and Holy Saturday
- April 15 = Resurrection of the Lord Jesus Christ - Easter

Gregorian calendar: 2000 AD, April 27: ephemeris of the Sun = +14º = 116.6202377 days = diameter of a year.

Length of the King's Chamber = 412.131378 inches

412.1316378 : 3.14159 = 131.1856855

Calendar: 131.1856855th day of a year = May 12th of the Gregorian and 29th April of the Julian calendar.

Julian calendar: 31 AD, April 29: ephemeris of the Sun = +14º = β = causeway's angle.

-------------------------------

*Julian calendar: the date of the equinox at the time of the birth of Christ fell on March 25 (Annunciation).
.

THE GREAT PYRAMID: TEMPLE OF KNOWLEDGE

2008-08-24T13:45:00.038-06:00

.
.................The Great Pyramid and the obliquity of the ecliptic.

Pi = 3.14159
10Pi = 31.4159 = one side of the square F

Area of the square F = 986.9587728 m2 = area of the circle E

Radius (r) of the circle E = 17.72453102 m
Diameter of the circle E = 35.44906205 m = AB

Base of the Great Pyramid = 231.92867 m = BC

1/2 of the Pyramid's base =115.964335 m = CD

BC + AB = 267.3777321 m

115.964335 : 267.3777321 = 0.433709771 = tangent of 23.44684885º = β = obliquity of the ecliptic.

King's Chamber:

- length = 412.1316378 (inches)

- width = 206.0658189 (inches)

a) AB = 35.4490625 m:

412.1316378 : 35.4490625 = 11.62602362 (x 31.4159 = 365.2419953)

206.0658189 : 35.4490625 = 5.813011808 (the Pyramid's height = 5813.011885 inches).

b) AB = 35.4490625 m = 1395.632382 inches:

412.1316378 : 1395.632382 = 0.295300999 = 2 x 0.147650499 (the Pyramid's height = 0.1476505019 km).

206.0658189 : 1395.632382 = 0.14765050499

c) AB = 35.4490625 m = 55.82529528 sacred cubits:

412.1316378 : 55.82529528 = 7.382524996 = 14.76504999 : 2

--------------------------

THE TEMPLE OF METROLOGY (I)

2008-08-21T18:46:00.121-06:00

.
.........................Figure 1, The Great Pyramid and Temple

On the east side of the Great Pyramid is the Temple of metrology with its basalt base, a rectangular building measuring about 171 feet from north to south and about 132 feet from east to west. Patches of the black basalt paved courtyard remain along with the sockets which held huge fifty granite pillars that formed a colonnade around the courtyard. From the Temple a causeway leads off in a straight line at an angle 14º North of due East:

.............................Figure 2, The Temple of metrology

Basalt base (pavement):
basalt = lava

When basaltic lava cools, it shrinks. In thick sheets of basaltic lava, this shrinking can produce shrinkage cracks that often occur in a hexagonal pattern and create hexagonal columns* of rock, a process known as columnar jointing:

...Figure 3, Basalt hexagonal patterns, Devils Postpile National Monument, California

....................................... Figure 4, Hexagon

Temple = 50 pillars (Figure 2)

Base of the Great Pyramid (four sides) = 927.71468 meters:

927.71468 : 50 = 18.5542936 m = 1/100 of one minute (1') of Longitude.

Angle of the Temple's causeway = 14º

Tangent 14º = 0.249328002

(927.71468 : 2) : 0.249328002 = 1860.430181 m

1860.430181 : 4 = 465.1075454 = AB (Figure 6)

Hexagon = 6 triangles

1 triangle = 3 sides

6 triangles = 18 sides

465.1075454 : 18 = 25.83930808 = r (Figure 4) = radius of the circle A (Figure 5).

......................................... Figure 5

Figure 5:

Radius of the circle A = 25.83930808 m

Area of the circle A = 2097.544899 m² = area of the square B = 45.79896176² = 52.12661939 x 40.23941939 m = 171.0190925 x 132.0190925 feet = dimensions of the Temple of metrology.

......................Figure 6, April 27: ephemeris of the Sun +14º

Figure 6:

β = causeway's angle = 14º

AB = 465.1075454 m

BC = 115.964335 m = 1/2 of the Pyramid's base = position of the Temple = C.

April 26-28th**: ephemeris of the Sun = +14º

Gregorian calendar: April 27th = 116.2602377th day of a year = diameter of a year:

.................
.................Figure 7, Diameter of the circle A = 116.2602377 days

Figure 7:

Circle A (circumference) = 365.242 days = 1 year

Diameter of the circle A = 116.2602377 days

Area of the circle A = area of the circle B

Every side of the square B = 103.0329095 days

April 27 of the Gregorian calendar is April 14 of the Julian calendar = 103.0329095-th day of a year.

....................Figure 8, Diameter of the circle 103.0329095 days

Figure 8:

d = 103.0329095 days

Area of the circle = area of the square

AB = 91.3105 days = BC = CD = DA = Seasons

........................................... Figure 9

Figure 9:

Radius (r) of the circle B = 103.0329095 days (1/2 of the King's Chamber width = 103.0329095 inches).

Area of the circle B = 33,350.42967 days = area of the square A

One side of the square A = 182.621 "days" = 1/2 of a year

Angle β = 32.48165854º = north "air-channel" of the King's Chamber (ascend).
Tangent 32.48165854º = 0.63662031:

103.0329095 x 0.63662031 = 65.59284278 days = radius of the circle C:

(2 x 65.59284278) x 3.14159 = 412.131638 days = circumference of the circle C = length of the King's Chamber (in inches).

412.131638 days = 1.128379644 years:

1.128379644² = 1.273240621 = tangent of the Pyramids angle of arise.

Circle C (area) = 13,516.44286 "days" = area of the square A1.

One side of the square A1 = 116.2602377 days

Year 31 AD (Julian callendar):

April 13 (26th): Great and Holy Friday
April 14 (27th): Great and Holy Saturday, the day when was the Lord Jesus Christ lead out Adam, Eve and other righteousness from the Hell into Heavenly Kingdom.
April 15 (28th): Resurrection of the Lord Jesus Christ.

Earth's equatorial diameter = 12.757.00336 (km):

(12.757.00336 : 10) - 465.1075454 = 810.5927906 = length of the Causeway (in meters):

"The total length of the causeway from the east face of the Great Pyramid to the site of the lower temple is not less than 810m"***
---------------------------------

*Basalt: http://www.youtube.com/watch?v=-G8lDJgPaaM

**Ephemeris for the Sun: http://eclipse.gsfc.nasa.gov/TYPE/TYPE.html
***Length of the causeway: http://www.zahihawass.com/egyptian_hist_dev_khufu.htm

THE SIGN OF THE SOLOMON'S TEMPLE

2008-08-18T14:27:00.026-06:00

.
......................... Thomas Ustick Walter: Solomon's temple*

Solomon’s temple (measurements in sacred cubits "cubit of the old standard"):

- height (portico) = 120
- length = 60
- height (temple) = 30
- breadth = 20

The numbers of the Temple are the code:
- number 120
- number 60
- number 30
- number 20

Equatorial diameter of the Earth = 12,757.00336 km = 20,089,769.07 sacred cubits:

20,089,769.07 : 120 = 167,414.7423 sacred cubits

167,414.7423 : 60 = 2790.245704 sacred cubits

2790.245704 : 30 = 93.00819014 sacred cubits

93.00819014 : 20 = 4.650409507 sacred cubits = 2 x 2.325204754 sacred cubits = 2 x 147.6505019 cm = 1/100 of the height of the Great Pyramid.

Equator of the Earth = 40,077.27418km:

40,077.27418 : 120 = 333.9772848

333.9772848 : 60 = 5.566288081

5.566288081 : 30 = 0.185542936

0.185542936 : 20 = 0.0092771468km = 9.2771468m = 40,077.27418/4320000

Base of the Great Pyramid = 231.92867m

231.92867 x 4 = 927.71468m

"Then David gave his son Solomon the plans for the portico of the temple, its buildings, its storerooms, its upper parts its inner rooms and the place of atonement. He gave him the plans of all that the Spirit had in his mind for the courts of the temple of the Lord and all the surrounding rooms for the treasuries for the dedicated things." (1 Chron. 28, 11-12)

"David said: - All this I have in writing from the hand of the Lord upon me, and he gave me understanding in all the details of the plan." (1 Chron. 28, 19)
-------------------------
*Solomon's temple:
http://www.philaathenaeum.org/tuw/ancient.html

GET WISDOM, GET UDERSTANDING

2008-08-16T06:54:00.027-06:00

.Height of the Great Pyramid = 147.6505019 m

Base of the Great Pyramid = 231.92867 m

Two sides of the Pyramid's base = 463.85734 m (at the equator, the Earth rotates at a speed of 0.46385734 km/s).

The Great Pyramid's angle of ascend ( β) = 51.85399754º

Tangent of 51.85399754º = 1.273240621

North "air-channel" of the King's Chamber (ascend) = 32.48165854º

Tangent of 32.48165854º = 0.63662031 = 1.273240621/2

(1 : 231.92867 ) x 147.6505019 = 0.63662031

CKD = d = 1
C = 3.14159 = Pi

1 : 0.63662031 = 1.570795 = Pi/2

0.63662031 : 147.605019 = 0.00431167

0.00431167 x 231.92867 = 1
----------------------------------
.

THE EARTH'S FOUNDATION

2008-08-15T19:16:00.013-06:00

Number Pi = 3.14159

Circumference of the circle C = 3.14159

Diameter of the circle C (d) = 1

Height of the Great Pyramid = 147.6505019 m

Base of the Great Pyramid = 231.92867 m

Two sides of the Pyramid's base = 463.85734 m

1 : 147.6505019 = 0.00677275

0.00677275 x 463.85735 = 3.14159 = C

THE LORD HAS DONE THIS

2008-08-14T21:24:00.015-06:00

. Measurements:

Number Pi = 3.14159

Diameter of the Sun = 1,392,000 (km)

Radius of the Sun = 696,000 (km)

Base of the Great Pyramid = 231.92867 (m)

Height of the Great Pyramid = 147.6505019 (m)

(1,392,000 : 3.14159) : 147.6505019 = 3000.922653

3000.922653 x 231.92867 = 696,000

WHAT WE SEE?

2008-08-13T11:32:00.024-06:00

.....................................Figure 1 (click to see)

Diameter:

a) Sun = 1,392,000 km

b) Earth = 12,757.00336 km

1,392,000 : 12,757.00336 = 109.1165347 km

Since Orion’s belt of three bright stars lies upon the celestial equator, Orion is visible from every inhabited part of the globe. Between the end of April to the middle of August belt of Orion is invisible to us, because it travels behind the Sun (Figure 1).

Proportion of the Sun's -Earth's dimensions = 109.1165347

April 24 - August 11 = 109.1165347 (110th) days = stars "travel" behind the Sun (daily Earth's movement on the Sun's diameter = 12,757.00336 km or 0.1476505019 km/s = height of the Great Pyramid)..
.

THE PYRAMID'S TENTH PART

2008-07-30T20:01:00.022-06:00

.

................Figure 1........................................Figure 2

Dimensions in inches (Figure 2):

EA = 913.105 = BF
AB = 7304.84 = DC
AD = 1162.062377 inches = BC = 36th row from the natural rock base (35th row from the pavement) = spot A5 (Figure 1) = DC course.

AB + BF = 1826.21 inches = 4638.5734 cm = 1/10 of the equatorial Earth's speed around own axis (in one second)*.

AB = 7304.84 inches = 0.185542936 km = 1/10 of the one minute of latitude on the Earth's equator.

Circle S (circumference) = 22,948.8123 inches = 0.5828998323 km

If a certain object was to travel with a speed of 0.5828998323 km/sec., for 24 hours it would travel a distance of 50,362.54551 km.

Earth's equator = 40,077.27418 km

50,362.54551 : 40, 077.27418 = 1.256636 km = 12.56636 dkm (dekameters) = 4Pi (4 x 3.14159)

CD course-thicknesses = 50 inches
Height of the Great Pyramid = 5813.011885 inches:

5813.011885 : 50 = 116.2602377 inches = length of the Antechamber = 1/10 of the AD (BC) height.
-------------------------------
The word "pyramid":

http://greatpyramid.blogspot.com/2008/05/word-pyramid.html

TRANSFORMATION OF THE GEOMETRY

2008-07-26T10:34:00.011-06:00

The Great Pyramid:

A-B = 231.92867 m

H = 147.6505019 m

Area ABCA = 17,122.19227 m2 = area of the square B = area of the circle A

Side C (square B) = 130.851795 m

Diameter d (circle A) = 147.6505019 m = 0.1476505019 km = H

Circle A (circumference) = 0.46385.734 km

1 day = 24 hours = 1440 minutes = 86,400 seconds

0.1476505019 x 86,400 = 12,757.00336 km = length of the Earth's equatorial diameter.

0.46385734 x 86,400 = 40,077.27418 km = length of the Earth's equator.

GEOMETRY AND THE ASCENDING PASSAGE

2008-07-22T11:45:00.027-06:00

.............................................Figure 1

Angle of the Ascending passage = 26.3026897º = β =BE-EP
EP = to Ecliptic Pole
γ = 63.6973103º

...........................................Figure 2

tan β = 0.494289195
sin β = 0.443113275
cos β = 0.896465629

Height of the Great Pyramid (ED) = 147.6505019 m = ED

147.6505019 x 0.443113275 = 65.42589745 m = EL (Figure 1) = C (Figure 2)

Area of the square B = Area of the circle A

Diameter (d) of the circle A = 73.82525085 m = 147.6505019/2.

THE WISDOM FROM THE SKY

2008-07-20T09:29:00.019-06:00

................................................Figure 1

North Celestial Pole (NCP)= 90º
Angle of the Ascending passage = 26.3026897º = β

90º - 26.3026897º = 63.6973103º

The Ascending passage (Descending passage) of the Great Pyramid is perfectly aligned with the center of the Ecliptic Pole (EP).

26.3026897º:
tangent = 0.494289195
sinus = 0.443113275
cosinus = 0.896465629

.............................................Figure 2

C = 6378.50168 km = Earth's equatorial radius

Area of the square B = area of the circle A

Radius of the circle A = 3592.78988 km

3592.78988 : 0.896465629 = 4007.727418 (Earth's equator = 40,077.27418 km).

Length of the King's Chamber = 412.1316378 inches:

412.1316378 x 0.443113275 = 182.621 inches = 50th part of the Great Pyramid's base.

If a certain object was to travel with a speed of 182.621 inches in one second, for 24 hours it would travel a distance of 157,745.4 inches = 400.7727418 km = 100th parth of the Earth's equator.
.

ASCENDING PASSAGE AND THE EARTH

2008-07-20T06:38:00.043-06:00

..........................................Figure 1

North Celestial Pole (NCP)= 90º
Angle of the Ascending passage = 26.3026897º = β

90º - 26.3026897º = 63.6973103º = the angle of the Ascending passage doesn't point to the star Thuban.

Thuban (Alpha Draconis) declination (DEC) = +64.37583333º

90º- 64.37583333º = 25.62416667º

90º - 26.3026897º = 63.6973103º = the angle of the Ascending passage doesn't point to the star Thuban.

The Ascending passage (Descending passage) of the Great Pyramid is perfectly aligned with the center of the Ecliptic Pole (EP).

Angle of the Ascending passage = 26.3026897º
Tangent = 0.494289195
Sinus = 0.443113275
Cosinus = 0.896465629

SINUS 26.3026897º = 0.443113275

........Figure 2

Earth:
Equatorial radius = 6378.50168 km = d/2
Area of the circle A = 127,816,488.4 km2 = area of the square B
C = 11,305.59509 km

6378.50168 x 0.443113275 = 2826.398773 km

2826.398773 x 4 = 11,305.59509 km = C (Figure 2).

Antechamber:
length = 116.2602377 inches

116.2602377 x 0.443113275 = 51.51645468 inches

51.51645468 x 4 = 206.0658187 inches = width of the King's Chamber.

The Great Pyramid:
height = 14,765.05019 cm

14,765.05019 x 0.443113275 = 6542.589745 cm

If a certain object was to travel with a speed of 6542.589745 cm in one second, for 24 hours it would travel a distance of 5652.79754 km:

5652.79754 x 2 = 11,305.59508 km = C (Figure 2).

The Great Pyramid:
slope angle = 51.85399754
tangent = 1.273240621

...........................................Figure 3

1.273240621 x 0.443113275 = 0.564189821 = C (Figure 3).

d = 0.636620309 = tangent of the angle of King's Chamber North channel = 1.273240621/2

ANGLE OF THE ASCENDING PASSAGE

2008-07-19T10:18:00.062-06:00

The arrows show the Earth's axis-movement (the stars move in the opposite way)

NCP = North Celestial Pole (North Celestial Pole is up from the horizon exactly an angle equal to your latitude).
EP = Ecliptic Pole
EP-NCP = 23.4461943º
GP-NCP = 30º = position of the Great Pyramid = 30º N
β = 26.3026897º = GP-EP = angle of the Great Pyramid's Ascending passage

The Ecliptic Pole (EP) is the point on the celestial sphere where the sphere meets the imaginary line perpendicular to the ecliptic plane, the path the Earth travels on its orbit around the Sun.The North Ecliptic Pole is in the constellation Draco.

Precession of the Equinoxes: the positions of the poles and equator on Earth do not change, only the orientation of the Earth against the fixed stars.

NCP = 90º
Angle of the Ascending passage = 26.3026897º

90º - 26.3026897º = 63.6973103º = the angle of the Ascending passage doesn't point to the star Thuban.

Thuban (Alpha Draconis) DEC = +64.37583333º

Biblical chronology: 2626 BC = Great Flood (Noah's Flood).

2000 AD: North Celestial Pole and Thuban (Alpha Draconis)

NCP-Thuban = 90º - 64.37583333º = 25.62416667º

Angle of the Ascending passage = 26.3026897º = the angle of the Ascending passage doesn't point to the star Thuban.

The rate of general precession is 50.291 arc seconds per year:

231,753 : 50.291 = 4608.240043 years

4608.240043 - 2000 AD = 2608 BC = Thuban was the polar star.

----------------------------------
North Celestial Pole:

http://calgary.rasc.ca/images/radec_polar_anim.gif

http://www.earthportals.com/Portal_Messenger/draco/dracangx.jpg

TWO BASES OF THE PYRAMID

2008-07-15T12:41:00.003-06:00

*
"The materials available for a discussion of the original size of the base of the Great pyramid are:— (1) the casing in situ upon the pavement, in the middle of each face; (2) the rock cut sockets at each corner; (3) the levels of the pavement and sockets; and (4) the mean planes of the present core masonry." (F. Petrie, The Pyramids and Temples of Gizeh, p.37)

..........................................Figure 1

Tangent β = 1.273240621

First base (red line, Figure 1) = 365.242 sacred cubits = 9131.05 inches = 23,192.867cm = 231.92867m

√23,192.867 = 152.2920451cm = 2AB

23,192.86 - 152.2920451 = 23,040.57495cm = 230.4057495m = length of the Second base (blue line, Figure 1).

152.2920451 : 2 = 76.1460226cm = AB = 29.97874906 inches*

76.1460226 x 1.273240621 = 96.9522091 cm = d = 38.17016106 inches**

C = 304.5840906cm = 2 x 152.2920451
------------------------------------------------

...........................................Figure 2

d = 96.9522091 : 2 = 48.47610449cm

C = 42.9608109cm

4C = 171.8432436cm

171.8432436 : 152.2920451 = 1.128379644

1.128379644² = 1.273240621

171.8432436 x 152.2920451 = 26,170.359cm = 412.1316379 sacred cubits = 10,303.29095 inches = 25 lengths of the King's Chamber.

-------------------------------------------------

Symbolism and fakts

Length of the First base in centimeters = 23,192.867cm
Length of the Second base in centrimeters = 23,040.57495cm

Diference between two bases = 152.2920451cm

Length of the First base of the Great Pyramid = 365.242 sacred cubits = 365.242 days = 1 year

365.242 : 152.2920451 = 2.398299923

2.398299923 : 3.14159 = 0.76340322 days

152.2920451 x 0.76340322 = 116.2602377

116.2602377 x 3.14159 = 365.242

152.2920451 : 0.76340322 = 199.4909651

1 sacred cubit = 63.5cm

199.4909651 : 63.5 = 3.14159 = Pi

1 inch = 2.54cm

199.4909651 : 2.54 = 78.53975004

78.53975004 x 4 = 314.159 = 100Pi

These measuremants and numbers can only be found if we use the metric system. The ancient Egyptians did not know of the metric system, which means that they were not the builders of the Great Pyramid. What do you think, who was the architect who was familiar with the metric system during that ancient time?

-----------------------------

* "Therefore, when reducing my observations, after the first winter, I found that the casing on the North side (the only site of it then known) lay about 30 inches inside the line joining the sockets..." (F. Petrie, The Pyramids and Temples of Gizeh, p.37) http://www.ronaldbirdsall.com/gizeh/petrie/c6.html#20

** "In computing the above quantities, I have used my final determination of the socket levels below the pavement; these, with the first approximate results, and Inglis's figures, stand thus:—

.....Accurate in 1882 ........Approx in 1881....... Inglis in 1865

N.E.....– 28.5..........................– 28.7....................– 28.6
S.E......– 39.9..........................– 39.9....................– 42.4
S.W.....– 23.0..........................– 22.9....................– 23.0
N.W.....– 32.8..........................– 32.6....................– 32.8 "
.
(F. Petrie, ibid. p. 40)
.

THE GREAT PYRAMID - EARTH

2008-07-06T13:29:00.007-06:00

- β = Pyramid's angle = 51.85399754º (tangent = 1.273240621).
- 45º = the angle of the south shannel of the King's Chamber.
- 32.48165854º = the angle of the north channel of the King's Chamber (tangent = 0.63662031).

Circle G = Earth
C-E = Earth's radius = 6378.501681 km:

6378.501681 x 0.63662031 = 4060.6837 km = E-L

4060.6837 x 3.14159 = 12,757.00336 km = Earth's equatorial diameter = W-E = A-B =B-D =D-F = F=A

A-B =B-D =D-F = F-A = 151,028.01344 km = circle R

Radius of the circle R = 8121.367435 km = C-N:

8121.367435 : 1.273240621 = 6378.501681 km = C-W = Earth's radius.

If a certain object was to travel with a speed of 2 Sacred Cubits ( 50 inches = 127 cm) in a second, for 24 hours (1 day) it would travel a distance of 109.728 km = 1000 skeins*:

51,028.01344 : 109.728 = 465.0409507 days = 1.273240621 years = tangent β

Great Pyramid's base = 365.242 Sacred Cubits (SC):

365.242 x 8 = 2921.936 SC = 185,542.936 cm = 1.85542936 km = 1' ( 1 minute) of the Earth's length on the Equator:

1º = 60' = 111,3257616 km

---------------------------------

* Skein: http://greatpyramid.blogspot.com/search?q=SKEIN
.

THE GREAT PYRAMID

2008-07-04T14:20:00.006-06:00

Angle C-B-E = 26.3026897º

A-B = 365.242 Sacred Cubits (SC)

C-D = 232.5204754 SC
H-K = 206.065819 SC

Radius of the circle = 116.2602377 SC

a) Volume of the sphere with the radius of 116. 2602377 SC = 6,582,363.505 cubic. Sacred Cubits.

Volume of the Great Pyramid = 10,339,543.67 cubic. Sacred Cubits:

10,339,543.67 : 6,582,363.505 = 1.570795 = Pi/2
.

METROLOGY

2008-06-29T10:24:00.021-06:00

.
a) Earth's equator = 40,077.27418 km = 4,007,727,418 cm = 63,113,817.61 sacred cubits.

b) Greenwich Meridian - Great Pyramid = 3456 km = 345,600,000 cm = 5,442,519.685 sacred cubits.

63,113,817.61 : 5,442,519.685 = 11.5964335 sacred cubits

If a certain object was to travel with a speed of 11.5964335 sacred cubits in one second, for 24 hours it would travel a distance of 1,001,931.855 sacred cubits. For the amount of time of one year (365.242 days) this distance would be 365,947,594.4 sacred cubits:

365,947,594.4 : 63,113,817.61 = 5.79821675 sacred cubits

Greenwich Meridian - Great Pyramid = 3456 km = 345,600,000 cm = 5,442,519.685 sacred cubits:

5,442,519.685 x 5.79821675 = 31,556,908.8 sacred cubits = 20,038.63709 km = 1/2 of the Earth’s Equator.
.
Symbolism: 365.242 days = 365.242 centimeters

365.242 cm x 2 = 730.4840001 cm

If a certain object was to travel with a speed of 730.4840001 cm in one second, for 24 hours it would travel a distance of 63,113,817.61 cm:

Earth's equator = 4,007,727,418 cm

4,007,727,418 : 63,113,817.61 = 63.5 cm = 1 sacred cubit.

If a certain object was to travel with a speed of 63.5 cm in one second, for 24 hours it would travel a distance of 54.864 km. For the amount of time of one year (365.242 days) this distance would be 20038.63709 km = 1/2 of the Earth's equator.

1 sacred cubit = 25 inches = 2.083333333 feet = 63.5 cm = 0.5 second

The English and Greek Foot (1 ft) defined from the Equator of the Earth as one 360,000th part of a day (angular movement of the Sun in a day) = 0.24 second.

1 sacred cubit = 172,800th part of a day (angular movement of the Sun in a day) = 0.5 second.
.

EARTH = TIME = LENGTH = WEIGHT

2008-06-27T13:30:00.012-06:00

.
EARTH

Earth's Equator = 40,077.27418 km

TIME:

1 day = 24 hours = 1440 minutes = 86,400 seconds

1 year = 365.242 days

40,077.27518 : 365.242 = 109.728 km/day = 10,972,800 cm/day = length

LENGTH: .
10,972,800 : 360,000 = 30.48 cm = 12 inches = 1 foot

"The English and Greek Foot 1 = 1.000000 ft defined from the Equator of the Earth as one 360,000th part of a day (angular movement of the Sun in a day) ..."

1 day:

1 : 360,000 = 0.000002778 days = 0.000066667 hours = 0.004 minute = 0.24 seconds = 1 foot

1 : 0.24 = 4.166666667 = weight

WEIGHT:
.
Golden karat:

"Karats are a measurement of gold's purity; a karat is 1/24 part, by weight, of the total amount."

1 : 24 = 0.041666667
-----------------------------------------
Foot: http://www.matrixofcreation.co.uk/sacrednumber/metrology/Metrology-Appendix_Richard-Heath.php

Golden karat: http://www.amnh.org/exhibitions/gold/incomparable/language.php

.

EARTH, GREENWICH AND INCH

2008-06-22T08:26:00.005-06:00

.
a) The Equator = 40,077.27418 km = 4,007,727,418 cm = 1,577,845,440 inches,
b) Greenwich Meridian - Great Pyramid = 3456 km = 345,600,000 cm = 136,062,992.1 inches:

1,577,845,440 : 136,062,992.1 = 11.5964335 inches

If a certain object was to travel with a speed of 11.5964335 inches in one second, for 24 hours it would travel a distance of 1001,931.855 inches. For the amount of time of one year (365.242 days) this distance would be 365,947,594.4 inches:

a) The Equator = 1,577,845,440 inches,
b) Greenwich Meridian - Great Pyramid = 13,062,992.1 inches,

365,947,594.4 : 1,577,845,440 = 0.23192867 inches ( the base of the Great Pyramid = 0.23192867 km).

136,062,992.1 x 0.23192867 = 31,556,908.79 inches = 80,154,548.34 cm = 801.5454834 km = 50-th part of the Earth’s Equator.
.

NOAH'S ARK

2008-06-13T15:59:00.013-06:00

God said to Noah:

“ So make yourself an ark of cypress wood; make rooms in it and coat it with pitch inside and out.This is how you are to build it:the ark is to be 300 cubits long, 50 cubits wide and 30 cubits high.
Make a roof for it and finish the ark to within 1 cubit of the top. “ (Gen.6,14–16)

The volume of these measurements with the roof part of the Ark is 7,148,437,500 cubic inches = 117,141,987.5 liters. Specific gravity of cypress wood* is 0.51 g/cm3:

117,141,987.5 x 0.51 = 59,742,413.6 kg

Earth weights 59,742,413,600,000,000,000,000,000,000 kg

According to the Great Pyramid the mean size of Earth is 40,017.93119 km, and its mean volume gives 1,082,215,220,000 km3. With the weight of Earth which Noah’s ark shows, and according to the mean size of the Earth, we get the specific weight of the Earth to be 5.520381944 g /cm3.
--------------------------

* "Greek word for cypress, kuparisson, and the resemblance of this word's base, kupar, to the Hebrew word gophar."*

Greek word: κυπαρίσσι
Latin word: Cupressus

a) Greek: Kυπαρίσσι

b) Latin: Cupressus

c) Hebrew: ?

Morphology:

a) Greek: Kamel
b) Latin: Camel

c) Hebrew: Gamel

d) Greek: Kupar
e) Latin: Cupar

f) Hebrew: Gupar (Gophar)

Hebrew: P = F(PH) = gupar = guphar (gophar) = gpr = gfr = rpg = rfg = גףר

Gopher:

http://en.wikipedia.org/wiki/Gopher_wood

http://www.christiananswers.net/q-eden/gopherwood.html

Hebrew alphabet:

http://en.wikipedia.org/wiki/Hebrew_alphabet

JUNE 21 (SUMMER SOLSTICE)

2008-06-10T18:29:00.024-06:00

..........Figure 1............................................Figure 2

The center of the Great Pyramid's base (1/2 of the base) = 4565.525 inches:

4565.525 : 3.14159 = 1453.25297 = diameter of the circle G = A-B in kilometers (Figure 2).

Radius of the circle G = 726.6264853 km = in meters distance from the center of the Great Pyramid to the line of the center of the Third Pyramid (spot X, Figure 1):

726.6264853 km on the curved Earth's surphace = 6.546184552º = α (Figure 2) = B = position of the pyramids of Giza on 21 June (Summer Solstice).

The angle of the ecliptic = 23.4461943º

23.4461943º + 6.546184552º = 29.99237885º

Position of the pyramids of Giza = 30º N

DOT AND THE GREAT PYRAMID

2008-06-09T15:57:00.039-06:00

.
D = dot = circle D
Circle D (circumference) = 1= whole, one unit, first

1 : 3.14159 = 0.318310155 = d

0.318310155 x 2 = 0.63662031 = tangent of 32.48165854º = angle of ascend of the King's Chamber north "air channel".

0.318310155 x 4 = 1.273240621 = tangent of 51.85399754º = angle of rise of the Great Pyramid.

a = 0.282094911

√1.273240621 = 1.128379644 = 4a = square E

1.128379644 years = 412.1316378 days = length of the King's Chamber (in inches).

1.128379644 x 0.282094911 = 0.318310155 = d

1 year = 365.242 days:

365.242 x 0.282094911 = 103.0329091 days = days from January 1 - April 14 = 1/4 of the King's Chamber length (in inches).

√3.14159 = 1.772453102

1.772453102 x 2 = 3.544906205

3.544906205 x 0.28209491 = 1

THE YEARS OF ADAM

2008-06-04T18:37:00.008-06:00

.
"And God formed the man of dust of the earth..." (Gen.2,7)

"And the days of Adam, which he lived were 930 years, and he died." (Gen.4,5)

The sides of the Great Pyramid rise at an angle of 51.85399754º
Tangent = 1.273240621

930 : 1.273240621 = 730.4196745 = 2 x 365.2098373 years

1 year = 365.242 days

Symbolism: 1 day = 1 year

365.242 years:

365.242 x 1.273240621 = 730.484 (two sides of the Great Pyramid = 730.484 sacred cubits).

730.484 x 1.273240621 = 930.0819018 years = 930 yeas and 30 days

"And God formed the man of dust of the earth..."
"And the days of Adam, which he lived were 930 years, and he died."
.

GOD'S MEASUREMENTS

2008-06-01T11:41:00.028-06:00

a) Mean Earth-Sun distance = 149,597,870 km (1 Astronomical unit - AU) = radius of the Earth's orbit around the Sun = E-S.

b) Diameter of the Earth's orbit = 299,195,740 km = 2-4

c) Diameter of the Sun = 1,392,000 km
.....Earth's diameter = 12,757.00336 km

.....1,392,000 : 12,757.00336 = 109,1165347

d) 1 year = 365.242 days

......365.242 : 109.1165347 = 3.347265389

e) Mean Earth's orbite around the Sun = 939,950,344.8 km = Z

.....939,950,344.8 : 3.347265389 = 280,811,419.3 km

f) 280,811,419.3km/109.1165347 days = 2,573,500.158 km/day = 107,229.1733 km/hour = 1787.152888 km/minute = 29.78588146 km/sec = Earth's speed around the Sun.

g) 1 AU = 149,597,870 km
.....Height of the Great Pyramid = 5813.011885 (inches)

.....Tangent β = 1.273240621

....If a certain object was to travel with a speed of 29.78588146 km/sec.,for 58.13011885 days it would travel a distance of 149,597,870 km = 1 AU = E-S = S-2 = S-1 = S-3

...If a certain object was to travel with a speed of 29.78588146 km/sec., for 116.2602377 days it would travel a distance of 299,195,740 km = diameter of the Earth's orbit around the Sun = 2-4 = 1-3

....116.2602377 x 3.14159 = 365.242 days = 1 year

h) Earth's orbit = 939,950,344.8 km
......Earth's equatorial diameter = 12,757.00336 km

....939,950,344.8 : 12,757.00336 = 73,681.12387 km

i) 1 year = 365.242 days

....73,681.12387 : 365.242 = 201.732341 km

j) Height of the Great Pyramid = 0.1476505019 km

....201.732341 x 0.1476505019 = 29.7858814 km = Earth's speed around the Sun (in one second).

k) 939,950,344.8 : 4 = 234,987,586.2 = A-B = 1-2 = 2-3 = 3-4 + 4 = Earth's seasons.

EARTH'S SATELLITE MAP

2008-05-30T18:55:00.011-06:00

..Figure 1: Earth's satellite map...............Figure 2: Pyramid and the Earth

Earth's Equator = 40,077.27418 km.

Equatorial diameter = 12,757.00336 km

Pyramid's angle: 51.85399754 degrees (tangent = 1.273240621)

12,757.00336 : 1.273240621 = 10,019.31854 km = 1/2 of the Pyramid's base or 1/4 of the Equator (Figure 2).
.

THE GREAT PYRAMID - GREENWICH

2008-05-29T17:58:00.023-06:00

From the Great Pyramid to Prime Meridian of the world

The Great Pyramid = 31.13513514º East from the Prime Meridian

1º = 111 km

31.13513514º = 3456 km (distance beetwin the two blue lines).

a) Base of the Pyramid = 365.242 sacred cubits = 231.92867 meters

b) Coptic word for Pyramid is pyrmet = tenth part

231.92867 : 10 = 23.192867

3456 x 23.192867 = 80,154.54835

80,154.54835 : 2 = 40,077.27418 km = length of the Earh's Equator in kilometres.

c) 40,077.27418 : 3456 = 11.5964335 = 23.192867/2

d) The sides of the Great Pyramid rise at an angle of 51.85399754º (tangent = 1.273240621):

.
3456 : 1.273240621 = 2714.33358 km

Pi = 3.14159

If a certain object was to travel with a speed of 3.14159 dekameters/sec., for 24 ours (1 day) it would travel a distance of 2714.33358 km.

THE WORD "PYRAMID"

2008-05-29T16:03:00.014-06:00

What is the meaning of the word “pyramid”. What does the word and term mean?

The word Copt or Coptic simply means Egyptian. The word Copt or Coptic refers to the Christian population of Egypt. The Coptic people are the descendants of the ancient Egyptians.

The Coptic word pyrmet (pyr-met) meaning division of ten, tenth part.

Pyramid = division of ten

ALMIGHTY GOD ASKING

2008-05-25T09:28:00.033-06:00

The Moon is 0.273 times that of the Earth's size.

1º on the surface of the perfect Eearth's sphere = 111 km

Circle = 360º = 39,960 km = Earth's perfect circle = circle E

Radius of the circle E = 6359.836898 km

Area of the circle E = 127,069,541.2 km2 = area of the square A

ES = side of the square E = 11,272.51264 km.
.
The sides of the Great Pyramid rise at an angle of 51.85399754º = β

Tangent β = 1.273240621.
.
11,272.51264 x 1.273240621 = 14,352.62099 km = BS = side of the square B
.
Radius of the circle E = 6359.836898 km

Area of the square B = area of the circle D

Radius of the square D = 8097.602681 km

Radius of the Earth's perfect circle = 6359.836898 km

8097.602681 : 1.273240621 = 6359.836898 km

8097.602681 - 6359.836898 = 1737.765783 km = radius of the Moon's perfect circle = radius of the circle M:

1737.765783 : 6359.836898 = 0.273240621 = the Moon and Earth proportions.

Almighty God asking:

"Who is this hides counsel from me, and confines words in his hearth, and thinks to conceal them from me?
Gird thy loins like a man; and I will ask thee, and do thou answer me. Where wast thou when I founded the earth? Tell me now, if thou hast knowledge, who set measures of it, if thou knowest, or who stretched a line upon it? On what are its rings fastened, and who is he that laid the corner-stone upon it?
When the stars were made, all my angels praised me with a loud voice." (Job, 38, 2-7)

PYRAMIDISTS VS PYRAMIDOLOGISTS

2008-05-24T08:27:00.052-06:00

.
"The materials available for a discussion of the original size of the base of the Great pyramid are:
(1) the casing in situ upon the pavement, in the middle of each face;
(2) the rock cut sockets at each corner;
(3) the levels of the pavement and sockets; and
(4) the mean planes of the present core masonry." (W. M. Flinders Petrie, The Pyramids and Temples of Gizeh, p. 37)

................Figure 1...................................................Figure 2

.
What is the base? A base is foundation: lowest support of a structure. The Great Pyramid was built on the base of the ground's solid rock (red line, Figures 1-2).

What is the height? The vertical dimension of extension; distance from the base of something to the top! What is the real height of the Great Pyramid? It is height above ground level of the base to the top of the Pyramid, vertical distance from the base of the pavement to the top of the Pyramid.

Pyramidists*: the original base of the Great Pyramid casing on the platform (pavement), is of these dimensions:
.....................Length in inches:
N.......................9069.4
E.......................9067.7
S.......................9069.5
W......................9068.6
Mean.................9068.8
(The Pyramids and Temples of Gizeh by W. M. Flinders Petrie, page 39)

W. M. Flinders Petrie: Socket Sides:
....................Length in inches:
N......................9129.8
E......................9130.8
S......................9123.9
W.....................9119.2
(The Pyramids and Temples of Gizeh by W. M. Flinders Petrie, page 38:
http://www.ronaldbirdsall.com/gizeh/petrie/c6.html )

Pyramidologists**: original architectural dimension of the Gr. Pyramid's socket sides: 9131.5 inches:

9131.05 - 9130.8 = 0.25 inches = 0.635cm

------------------------------------------
*A pyramidist is an Egyptologist who specialises in the study of the pyramids of Egypt, a specialist on the Egyptian pyramids from the archeological standpoint.
**Pyramidologist is a scientist who deals with the Great Pyramid's scientific facts that correspond with the biblical truth.
.

TIME = SPEED = LENGTH

2008-05-23T21:22:00.012-06:00

.

Angle C-B - E: 26.3026897°
A-B = 365.242 Sacred Cubits (SC)
C-D = 232.5204754 SC
H-K = 206.065819 SC

Radius of the circle: 116.2602377 SC
Volume of the sphere (radius 116. 2602377 SC): 6,582,363.505 cub. Sacred Cubits,

Volume of the Gr. Pyramid: 10,339,543.67 cub. Sacred Cubits:

10,339,543.67 : 6,582,363.505 = 1.570795 ( 1/2 Pi )

Sacred Cubit

The English have a measurement of length, which they call skein* : 109.728 meters.
If a man was walk one day, with his every step 1 Sacred Cubit (63.5 cm) and with the speed of two steps in a second (2 Sacred Cubits or 127 cm), in 24 hours he would travel 109.728 km (1000 skeins). For one year of 365.242 days, he would travel around the planet Earth. That is, he would travel the length of the Equator: 40,077.27418 km:

The original ancient base-breadth was 760.9208333 present feet = 9131.05 inches = 23,192.867 centimeters = 365.242 Sacred Cubits. The differences between the originally and the present measurements were caused by the earthquakes and by the meteorological reasons: the Sun’s heat and the night’s coldness: the most sun exposed south side of the present Pyramid’s base is the longest side, and the north side, mostly in a shadow, is shortest.

One side of the Great Pyramid's base is 23,192.867 cm long. Two sides together have 46,385.734 cm: this is the length of speed of Earth's turning on the Equator in one second. For the amount of time of one minute one point on the Equator moves by 2,783,144.04 cm or 27.8314404 km. For one hour this is the length of 1669.886424 km. For the amount of 24 hours this is 40,077.27418 km. This is, according to the Great Pyramid, the length of Earth's Equator:

The height of the Great Pyramid is 14,765.05019 cm.

If a certain object was to travel on with a speed of 14,765.05019 cm in a second, it would travel a distance of 53,154,180.68 cm in one hour. For the amount of time of one day this distance would be 12,757.00336 km. This, according to the Great Pyramid, is the length of Earth's Equator.

14,765.05019 x 3.14159 = 46,385.734 cm = two sides of the Pyramid’s base.

More about Sacred Cubit:
---------------------------
* Skein:

http://orefa.org/length.html

http://www.onlineunitconversion.com/...field.U.S.html

http://www.themeter.net/lung_e.htm

http://www.convertit.com/Go/Entisoft.../Converter.ASP

BURJ DUBAI TOWER

2008-05-21T09:32:00.019-06:00

.

Burj Tower, Dubai. This Spot is geographically located at latitude (25.212841 degrees) 25° 12' 46" North of the Equator and longitude (55.300416 degrees) 55° 18' 1" East of the Prime Meridian on the Map of Dubai.

Arabian Peninsula (click on the map).

The Great Pyramid:
- Angle of rise = 51,85399754º
- Passage's angle = 26,3026897º

0 = Prime (Greenwich) meridian
A = 51,85399754º E
T = The Burj Tower, Dubai

A-B = 384,3903684 km = 3,462976292º

β = 26,3026897º
tan β = 0,49428918

The Burj Dubai's spire can be seen by a person 95km away on a clear day.

The Great Pyramid (base and height) = 597.7624754 sacred cubits

Circle D = 597.7624754 km

Radius of the circle D = 95.13693311 km

Diameter of the circle D = 190.2738662 km:

190.2738662 : 0.49428918 = 384.944291 km = 3.46796783º = A-B

The Great Pyramid's angle of rise = 51.85399754º
A = 51.85399754º E

51.85399754º + 3.46796783º = 55.32196537º = 50º 19' 19.075" = T = position of the Burj Tower East of the Prime Meridian (line B).

WHEN THE TIME HAD FULLY COME

2008-05-12T15:19:00.017-06:00

.
Astronomy: the precession of Earth's axis of rotation (general precession) = 50.291 seconds of arc per year or 1 degree every 71.6 years.
A complete precession cycle (360°) = 25,765 years

"And God said, Let there be lights in the firmament of the heaven to give light upon the earth, to divide between day and night, and let them be for signs and for seasons and for days and for years." (Septuagint: Gen.1, 14)

Nativity of Jesus Christ = 25 December 4 BC

From the end of the Creation to the 25 December 4 BC = 4278.983128 years.

The Great Pyramid (base + height) = 597.7624754 sacred cubits:

59.77624754º = 3586.574852 minutes = 215,194.4911 seconds

59,77624754º : 4278.983128 = 0.013969732º = 0,83818392 arc minutes = 50.2910352 seconds = general precession.

.4278.983128 : 59.77624754 = 71.58333459 years for 1º of the precession:

"But when the time had fully come, God sent his Son..." (Gal. 4, 4)

360º x 71.58333459 = 25,770 years = complete precession cycle.

-------------------------------------
* General precession:
http://www.astrosociety.org/education/publications/tnl/45/globe3.html

http://sci.esa.int/science-e/www/object/index.cfm?fobjectid=35696&fbodylongid=1686

THE GREAT SPHINX

2008-05-11T14:56:00.046-06:00

Earth's perfect circle

On the curved Earth's surface 1º = 111 km

360º = 39,960 km

(39,960 : 3.14159) : 2 = 6359.836898 km = side C of the square B

Area of the square B = 40,447,527.37 km2 = area of the circle B

Radius of the circle A = 3588.155246 km

Constellation Leo and the Great Sphinx

β = Denebola "tail of the lion" (Beta Leo):

RA 11h 49 04.43458416 = 11.8178985 hours
Dec +14 34 19 = +14.57194444º

O = Subra (Omicron Leo) *:

RA 09h 41 08.0 = 9.685555556 hours
Dec +09 53 32 = +9.892222222º

X-O = 2.13234294 hours = 31.9851441º

1 hour = 15º

1º of the curved Earth's surface = 111 km:

31.9851441º = 3550.350995 km on the Earth's surface.

X-B = 4.680055573º

4.680055573º on the Earth's surface = 519.4861686km

O-B = 3588.155246 km x 2 = 7176.310492 km on the Earth's surface:

7176.6310492 cm = 235.4432576 feet = length of the Great Sphinx.

------------------------------
* “Subra” was named from “sub” (lat.) meaning under or near, and “Ra”, name of the Egyptian god of the sun, meaning under or near the sun (could be “near to God” real easy!).
.

EARTH, SOLOMON’S TEMPLE AND THE PYRAMID

2008-04-26T08:39:00.012-06:00

.

Earth’s Equator = 40,077.27418 km = Circle A

Circle A = Earth

d = Equatorial diameter of the Earth = 12,757.00336 km
Area = 127,816,480.3 km²

Square B :
Area = 127,816,480.3 km² = area of the circle A
Side C = 11,305.59509 km = 1,130,559,509 cm.

Thomas Ustick Walter: Solomon's temple

Solomon’s temple:

Portal (high) = 120 Sacred Cubits
Length = 60 “ “
Width = 20 “ “
Height = 30 “ “

The numbers of the Temple are the code:
- Number 120
- Number 60
- Number 30
- Number 20

a) 1,130,559,509 : 120 = 9,421,329.241 cm
b) 9,421,329.241 : 60 = 157,022.154 cm
c) 157,022.154 : 30 = 5,234.071801 cm = 2,060.658189 inches
d) 5,234.071801 : 20 = 261.70359 cm = 103.0329095 inches

The Great Pyramid:

King’s Chamber:

- Length = 412.1316378 inches

- Width = 206.0658189 inches

- 1/2 of the Chamber’s width = 103.0329095 inches
---------------------------------------
Solomon's temple: http://www.philaathenaeum.org/tuw/ancient.html

.

SACRED GEOMETRY

2008-04-13T16:36:00.007-06:00

.
Sacred geometry (slideshows):
http://www.esnips.com//web/desnik2003-Sacredgeometry?action=showSlideShow#files?action=showSlideShow#files