.
DC = diameter of the circle Z = d
GD = radius of the circle Z = r
Angle β1 = Pyramid’s ascent = 51,85399754°
Tangent β1 = 1,273240621
Circumference: C = (d/tang. β1) x 4
Area: A = (r²/tang. β1) x 4
Angle β = ascent of the King’s Chamber north channel = 32,48165854°
Tangent β = 0,63662031
Circumference: C = (d/tang. β) x 2
Area: A = (r²/tang. β) x 2
Angle β2 = 17,65680115°GD = radius of the circle Z = r
Angle β1 = Pyramid’s ascent = 51,85399754°
Tangent β1 = 1,273240621
Circumference: C = (d/tang. β1) x 4
Area: A = (r²/tang. β1) x 4
Angle β = ascent of the King’s Chamber north channel = 32,48165854°
Tangent β = 0,63662031
Circumference: C = (d/tang. β) x 2
Area: A = (r²/tang. β) x 2
Tangent β2 = 0,318310155 = 1 : 3,14159
Circumference: C = d/tang. β2 = AB
Area: A = r²/tang. β2
DH = r/tang. β = KG = GL = AE = EC = CF = FB = 1/4 AB
DC = D/tang. β = AC = CB = 1/2 AB
Tangent of the angle α (Alpha) = 3,14159 = Pi
Tangent of the angle Alpha1 = 1,570795 = Pi/2
The rectangle’s Area = Area of the sphere around the circle Z